For the beam shown, the magnitude of the concentrated load is P = 28 kN, the magnitude of the couple is Mg = 200 kN-m, and the beam engths are a = 4.8 m and b = 14.4 m. a) derive equations for the shear force V and the bending moment. M for any location in the beam. Place the origin at point. A. b) use the derived functions to plot the shear-force and bending-moment diagrams for the beam. Use your diagrams to determine the magnitudes of the maximum shear force and the maximum bending moment.

For the beam shown, the magnitude of the concentrated load is P = 28 kN, the magnitude of the couple is Mg = 200 kN-m, and the beam engths are a = 4.8 m and b = 14.4 m. a) derive equations for the shear force V and the bending moment. M for any location in the beam. Place the origin at point. A. b) use the derived functions to plot the shear-force and bending-moment diagrams for the beam. Use your diagrams to determine the magnitudes of the maximum shear force and the maximum bending moment.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

For the beam shown, the magnitude of the concentrated load is P = 28 kN, the magnitude of the couple is Mg = 200 kN-m, and the beam
lengths are a = 4.8 m and b= 14.4 m.
(a) derive equations for the shear force V and the bending moment M for any location in the beam. Place the origin at point. A.
(b) use the derived functions to plot the shear-force and bending-moment diagrams for the beam. Use your diagrams to determine the
magnitudes of the maximum shear force and the maximum bending moment.
Note that answers may be positive or negative. Here, "maximum" refers to the largest magnitude value, but you should enter your shear
force and bending moment with the correct sign, using the sign convention presented in Section 7.2 of the textbook. If the magnitudes of
the largest positive and largest negative values are the same, enter a positive number.
P
a
MB
B
b
C
X

P
Answer:
Vmax=
Mmax =
a
MB
B
KN
kN.m
b
X

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