For example if my T = 169 how can i get the correct critical values out of a Dikey fuller test My books gets "As the appropriate critical value at the 5% level is −3.44" how did they get this
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For example if my T = 169 how can i get the correct critical values out of a Dikey fuller test
My books gets "As the appropriate critical value at the 5% level
is −3.44" how did they get this
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- You are a researcher who wants to know what the mean (µ) level of anxiety would be for the whole population if they were all receiving a new anti-anxiety therapy. You can’t give the therapy to the whole population, so you give it to a sample, and you get M = 32.1 as the average anxiety level for the sample on the therapy. What is the reason that you can’t just simply assume that µ = 32.1? You didn’t use random assignment Sampling error Descriptive statistics Inferential statisticsA researcher would like to examine how the chemical tryptophan, contained in foods such as turkey, can affect mental alertness. A sample of n = 9 college students is obtained and each student’s performance on a familiar video game is measured before and after eating a traditional Thanksgiving dinner including roast turkey. The average score dropped by M = 14 points after the meal with SS = 1152 for the difference scores. A. Is there is significant difference in performance before eating versus after eating? Use a two-tailed test with α = .05. SMD = ___________________________ tcritical = ________________________ tcalculated = ________________________ Decision = _______________________ B. Compute r2 to measure the size of the effect. r2 = _____________________________ C. Write a sentence demonstrating how the outcome of the test and the measure of effect size would…qiiip1. answer only pls 6. what is the critical value 7. what is the computed value 8. compare the computed value and the critical value. what is the relationship between two values 9. what is the statistical decision
- Is there a quick way to solve these kinds of problems with a TI-84? I spend a lot of time doing them by hand and I desperately need to speed up the process. Can you please walk me through the steps I need to do? please do not use excel, I will not have access to that.FACTORS FOR I AND R CONTROL CHARTS Observations in Sample, n dz A2 dz D3 D4 2 1.128 1.880 0.853 3.267 3 1.693 1.023 0.888 2.574 4 2.059 0.729 0.880 2.282 5. 2.326 0.577 0.864 2.114 6. 7. 2.534 0.483 0.848 2.004 2.704 0.419 0.833 0.076 1.924 8. 2.847 0.373 0.820 0.136 1.864 2.970 0.337 0.808 0.184 1.816 10 3.078 0.308 0.797 0.223 1.777 11 3.173 0.285 0.787 0.256 1.744 12 13 3.258 3.336 3.407 0.266 0.249 0.235 0.778 0.770 0.763 0.283 1.717 0.307 1.693 1.672 1.653 14 0.328 15 3.472 0.223 0.756 0.347 3.532 0.212 0.750 0.744 0.739 0.363 0.378 0.391 16 1.637 17 18 3.588 0.203 1.622 3.640 0.194 1.608 19 20 3.689 3.735 0.187 0.734 0.403 1.597 0.180 0.729 0.415 1.585 21 22 3.778 3.819 1.575 1.566 0.173 0.724 0.425 0.434 0.167 0.720 23 24 25 3.858 3.895 3.931 0.162 0.157 0.153 0.716 0.712 1.557 1.548 0.443 0.451 0.708 0.459 1.541Hi, i have one question. How was the level of significance obtained? at the beginning of the exercise it is clarified that it is (α)=0.05 but I don't know where this value comes from
- Suppose f(x) = 1/20 from 5 to 25. What is the 25th percentile of X? 10 1/20 None of the other choices is correct .25Previous Problem List Next A new cream that advertises that it can reduce wrinkles and improve skin was subject to a recent study. A sample of 61| women over the age of 50 used the new cream for 6 months. Of those 61 women, 52| of them reported skin improvement(as judged by a dermatologist). Is this evidence that the cream will improve the skin of more than 40% of women over the age of 50? Test using a = 0.05 (a) Test statistic: z = (b) Critical Value: 2* = (c) The final conclusion is O A. There is not sufficient evidence to reject the null hypothesis that p O B. We can reject the null hypothesis that p = 0.4 and accept that p > 0.4 That is, the cream can improve the skin of more than 40% of women over 50. 0.4 That is, there is not sufficient evidence to reject that the cream can improve the skin of more than 40% of women over 50.A sociologist of education wants to prove that students’ sense of mastery and control before a math test could increase if students had a chance to practice with examples of questions from typical tests. The sociologist has long studied sense of content’s mastery and emotional control pre-math test with a scale called NoStressM, which ranges from 0 to 50, where 0 indicates great stress, and 50 indicates great control and mastery. In the typical student population, the day before the math test, students score 20 points on average, with a standard deviation of 6 points. The sociologist selected at a random a sample of 60 students from different schools and 3 offered them to practice for a week with questions drawn from typical math tests. The day before the math test, she administered the NoStressM scale to the 60 students and found a sample mean of 23 and a standard deviation like the one in the population. Your turn: a) Formulate the null and the alternative hypotheses that fit this…
- A researcher wants to see if there is a difference in APGAR scores of newborns depending on whether the mother smoked during pregnancy or not. She collects data and analyzes the results using SPSS. What is the correct way to report the results in APA style? Question 23 options: t(58) = 3.288, p>.05 t(58) = 3.288, p= .002 t(26.5) = 3.278, p<.05 t(26.5) =3.278, p=.003A study is conducted to determine factors in solving missing persons cases. The outcome is Y; which is equal to 1 if the i-th missing person case is unsolved and 0 if it is solved. Let covariate X1; be an indicator equal to 1 if the i-th case is female and 0 for male. Let X2i be a categorical covariate of age group for the i-th case. Categories are less than 14 years old (base level/group), between 14 and 19 years old, and older than 19 years. Set u = P(Y = 1) and the following model is fit: logit(u) = Bo + BịI(Female) + B2I(14 to 19 yrs old) + B3I(> 19 yrs old) The output from the model is below: Estimate S.E. p-value Bo -4.565 0.128 0.380 0.087 B2 Вз -0.198 0.042 0.163 1.128 0.133 a. Using the logistic regression output, calculate the estimated odds ratio of a case being unsolved (again Y=1 is unsolved and Y=0 is solved) comparing females to males (female is the numerator odds) of the same age. Interpret this odds ratio in context of the problem. iii b. Create a 95% confidence…t has been suggested that gossiping about others may affect how likeable you are. Two groups of participants are asked to read a vignette describing a fictional person. They are then asked to rate how much they would like the person described in the vignette on a continuous scale from 1-15, where higher scores represent a higher likability. The first group of participants (n=20) reads a vignette describing a person that frequently gossips and obtains an average likability score of (M1) with a variance of (S12). The second group of different participants (n=20) reads a vignette describing a person that never gossips and obtains an average likability score of (M2) with a variance of (S22). Given that there is not much research in this area, test the hypothesis that gossiping impacts likability at an alpha=0.05. 1, Are the results you obtained meaningful? report the results here for your effect size showing all your work and your interpretation 2. Report the results of the study…