For circuit series and parallel, the supply voltage of, VSupply= 240 Volts, R₁= 202, R₂=300, R3=8N, R4-3002 and R5= 602. If resistor R4 is shorted in the circuit, what will be the total resistor for the new changed circuit? 40 Ω 60 Ω 20 Ω 100 Ω - I Vsupply

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**Educational Website Content: Series and Parallel Circuits**

**Circuit Analysis Question**

The problem describes a circuit involving both series and parallel arrangements of resistors with the following values:

- Supply Voltage, \( V_{\text{Supply}} \) = 240 Volts
- Resistor \( R_1 = 20 \, \Omega \)
- Resistor \( R_2 = 30 \, \Omega \)
- Resistor \( R_3 = 8 \, \Omega \)
- Resistor \( R_4 = 30 \, \Omega \)
- Resistor \( R_5 = 60 \, \Omega \)

**Scenario:**
Resistor \( R_4 \) is shorted in the circuit. The task is to determine the total resistance of the newly modified circuit.

**Diagram Explanation:**

The diagram shows a combination of series and parallel resistor configurations:

1. Resistors \( R_1 \) and \( R_2 \) are in series.
2. This series combination is parallel to \( R_3 \).
3. Resistor \( R_4 \) is originally part of the circuit but is shorted.
4. Finally, \( R_5 \) is connected to the parallel combination of \( R_3 \) and the series resistors \( R_1 \) and \( R_2 \).

**Options for the Total Resistance:**

- \( 40 \, \Omega \)
- \( 60 \, \Omega \)
- \( 20 \, \Omega \)
- \( 100 \, \Omega \)

To solve this, calculate the equivalent resistance with the changes mentioned.

**Quiz:**

Select the correct total resistance for the circuit once resistor \( R_4 \) is shorted.

- [ ] 40 \( \Omega \)
- [ ] 60 \( \Omega \)
- [ ] 20 \( \Omega \)
- [ ] 100 \( \Omega \)

**Instructions:**

Analyze the modified circuit to find the total resistance. Use series and parallel resistor equations to determine the resistance accurately.
Transcribed Image Text:**Educational Website Content: Series and Parallel Circuits** **Circuit Analysis Question** The problem describes a circuit involving both series and parallel arrangements of resistors with the following values: - Supply Voltage, \( V_{\text{Supply}} \) = 240 Volts - Resistor \( R_1 = 20 \, \Omega \) - Resistor \( R_2 = 30 \, \Omega \) - Resistor \( R_3 = 8 \, \Omega \) - Resistor \( R_4 = 30 \, \Omega \) - Resistor \( R_5 = 60 \, \Omega \) **Scenario:** Resistor \( R_4 \) is shorted in the circuit. The task is to determine the total resistance of the newly modified circuit. **Diagram Explanation:** The diagram shows a combination of series and parallel resistor configurations: 1. Resistors \( R_1 \) and \( R_2 \) are in series. 2. This series combination is parallel to \( R_3 \). 3. Resistor \( R_4 \) is originally part of the circuit but is shorted. 4. Finally, \( R_5 \) is connected to the parallel combination of \( R_3 \) and the series resistors \( R_1 \) and \( R_2 \). **Options for the Total Resistance:** - \( 40 \, \Omega \) - \( 60 \, \Omega \) - \( 20 \, \Omega \) - \( 100 \, \Omega \) To solve this, calculate the equivalent resistance with the changes mentioned. **Quiz:** Select the correct total resistance for the circuit once resistor \( R_4 \) is shorted. - [ ] 40 \( \Omega \) - [ ] 60 \( \Omega \) - [ ] 20 \( \Omega \) - [ ] 100 \( \Omega \) **Instructions:** Analyze the modified circuit to find the total resistance. Use series and parallel resistor equations to determine the resistance accurately.
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