For circuit series and parallel, the supply voltage of, VSupply= 240 Volts, R₁= 202, R₂=300, R3=8N, R4-3002 and R5= 602. If resistor R4 is shorted in the circuit, what will be the total resistor for the new changed circuit? 40 Ω 60 Ω 20 Ω 100 Ω - I Vsupply
For circuit series and parallel, the supply voltage of, VSupply= 240 Volts, R₁= 202, R₂=300, R3=8N, R4-3002 and R5= 602. If resistor R4 is shorted in the circuit, what will be the total resistor for the new changed circuit? 40 Ω 60 Ω 20 Ω 100 Ω - I Vsupply
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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![**Educational Website Content: Series and Parallel Circuits**
**Circuit Analysis Question**
The problem describes a circuit involving both series and parallel arrangements of resistors with the following values:
- Supply Voltage, \( V_{\text{Supply}} \) = 240 Volts
- Resistor \( R_1 = 20 \, \Omega \)
- Resistor \( R_2 = 30 \, \Omega \)
- Resistor \( R_3 = 8 \, \Omega \)
- Resistor \( R_4 = 30 \, \Omega \)
- Resistor \( R_5 = 60 \, \Omega \)
**Scenario:**
Resistor \( R_4 \) is shorted in the circuit. The task is to determine the total resistance of the newly modified circuit.
**Diagram Explanation:**
The diagram shows a combination of series and parallel resistor configurations:
1. Resistors \( R_1 \) and \( R_2 \) are in series.
2. This series combination is parallel to \( R_3 \).
3. Resistor \( R_4 \) is originally part of the circuit but is shorted.
4. Finally, \( R_5 \) is connected to the parallel combination of \( R_3 \) and the series resistors \( R_1 \) and \( R_2 \).
**Options for the Total Resistance:**
- \( 40 \, \Omega \)
- \( 60 \, \Omega \)
- \( 20 \, \Omega \)
- \( 100 \, \Omega \)
To solve this, calculate the equivalent resistance with the changes mentioned.
**Quiz:**
Select the correct total resistance for the circuit once resistor \( R_4 \) is shorted.
- [ ] 40 \( \Omega \)
- [ ] 60 \( \Omega \)
- [ ] 20 \( \Omega \)
- [ ] 100 \( \Omega \)
**Instructions:**
Analyze the modified circuit to find the total resistance. Use series and parallel resistor equations to determine the resistance accurately.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1b551779-a94f-4658-8ab9-cb1269496a60%2F35d5ae83-b8a9-4f1f-9931-4a5176ae8519%2Fct1spg3_processed.png&w=3840&q=75)
Transcribed Image Text:**Educational Website Content: Series and Parallel Circuits**
**Circuit Analysis Question**
The problem describes a circuit involving both series and parallel arrangements of resistors with the following values:
- Supply Voltage, \( V_{\text{Supply}} \) = 240 Volts
- Resistor \( R_1 = 20 \, \Omega \)
- Resistor \( R_2 = 30 \, \Omega \)
- Resistor \( R_3 = 8 \, \Omega \)
- Resistor \( R_4 = 30 \, \Omega \)
- Resistor \( R_5 = 60 \, \Omega \)
**Scenario:**
Resistor \( R_4 \) is shorted in the circuit. The task is to determine the total resistance of the newly modified circuit.
**Diagram Explanation:**
The diagram shows a combination of series and parallel resistor configurations:
1. Resistors \( R_1 \) and \( R_2 \) are in series.
2. This series combination is parallel to \( R_3 \).
3. Resistor \( R_4 \) is originally part of the circuit but is shorted.
4. Finally, \( R_5 \) is connected to the parallel combination of \( R_3 \) and the series resistors \( R_1 \) and \( R_2 \).
**Options for the Total Resistance:**
- \( 40 \, \Omega \)
- \( 60 \, \Omega \)
- \( 20 \, \Omega \)
- \( 100 \, \Omega \)
To solve this, calculate the equivalent resistance with the changes mentioned.
**Quiz:**
Select the correct total resistance for the circuit once resistor \( R_4 \) is shorted.
- [ ] 40 \( \Omega \)
- [ ] 60 \( \Omega \)
- [ ] 20 \( \Omega \)
- [ ] 100 \( \Omega \)
**Instructions:**
Analyze the modified circuit to find the total resistance. Use series and parallel resistor equations to determine the resistance accurately.
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