For box, examine the blocks attached to the balances. Based on their positions and sizes, determine which block is more dense (the dark block or the lighter-colored block), or if the relative densi- ties cannot be determined. (Think carefully about the information being shown.)
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- What is the ratio L/R for which the uniform wire figure can be balanced in the position shown?For box, examine the blocks attached to the balances. Basced on their positions and sizes, determine which block is more dense (the dark block or the lighter-colored block), or if the relative densi- ties cannot be determined. (Think carefullv about the information being shown.)Show only the free body diagram for each question given.
- Consider the two blocks on the seesaw below. The wedge is fixed at the center of the seesaw. If the larger box has twice the mass as the smaller, how could the seesaw be balanced? The distance measured from the center of the seesaw where the wedge is located is r. Note: For the larger box, r = rlarge and for the smaller box, r = rsmallHi! Help me get the required weight of the triangle to make the Gear 1 in equilibrium.NOTE: Units is in cm.Learning Goal: To use the equations of equilibrium for a three-dimensional object to solve for the support reactions. The plate shown in (Figure 1) is supported by a roller and a cable in the xx-direction at AA, a ball-and-socket joint at BB, and a roller at CC. A force FFF = 6.6 kNkN is applied at the centroid of the plate parallel to the yzyz-plane and making an angle of θθtheta = 34 ∘∘ with the xyxy-plane. The sides ABAB and BCBC of the plate have length LLL = 1.2 mm . What is the reaction force in the yy-direction at point BB? Let a positive force act in the positive yy-direction. What is the reaction force in the zz-direction at point CC? What is the reaction force in the zz-direction at point AA? What is the reaction force in the zz-direction at point BB? What is the tension TT in the cable? What is the reaction force in the xx-direction at point BB? Let a positive force act in the positive xx-direction.
- Hi! Help me get the required weight of the triangle to make the 1st gear in equilibrium. This time, gear 3 is 9 cm in diameter. Note: Units is in cm.Analytically solve and find the equilibrium. The given above is its experimental value.Learning Goal: To analyze a rod assembly in three-dimensional space and determine the support reactions by using the equations of equilibrium for a rigid body. The rod assembly shown has smooth joumal bearings at A, B, and C. The forces F 600 N. F-480 N. F 460 N, and F-900 N are applied as shown in the figure. The geometry of the rod assembly is given as a 0.900 m, &0.650 m, and c 0.800 m Neglect the weight of the rod Determine the magnitude of the 2 component of the reaction on the rod at A Express your answer to three significant figures and include the appropriate units. View Available Hint(s) Submit PA A₁ = Value Submit Part F- Finding the x component of the reaction at A Determine the magnitude of the x component of the reaction on the rod at A Express your answer to three significant figures and include the appropriate units. View Available Hint(s) Units μÁ Value ? Units ?
- A truss is facing a two-force member and both of them are in the opposite directions, and the truss is in equilibrium. And both of them are coming to each other. The forces are called Select one: O a. Tensile Forces O b. Compressive forces O c Parallel and collinear forces with same direction of heading O d. The rotational forces Next page est-3 Jump to...Im able to break down each component of AB. AC and AD. getting lengths and angles. But im not sure how to approach breaking down how the force is devided through each. I'm not sure how to show that even though AB and AD are the same distance and at the same angle from point A they dont share the same forces. I do know this problem should be solved by finding which rope would hold the most tension because that would be the first one to fail. Then we solve for the rest of the problem assuming that the tension on this rope is 690 to find the maximum possible net force.Resolve the 360-lb force into components along the cables AB and AC. Use =60 and =40.