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For an 18-8 Mo stainless steel (Animated Figure 8.36), predict the time to rupture for a component that is subjected to a stress of 80 MPa (11,600 psi) at 700°C (973 K). ! hours

For an 18-8 Mo stainless steel (Animated Figure 8.36), predict the time to rupture for a component that is subjected to a stress of 80 MPa (11,600 psi) at 700°C (973 K). ! hours

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Stress (MPa) 100 10 25 x103 12 x103 T(20 + log t)(°R-h) 35 x103 30 x103 16 x103 40 45 x103 x103 24 x103 20 x103 T(20 + log t.)(K-h) 50 x103 28 x103 10,000 100,000 23.26. 10³ (K-h) 1000 Larson-Miller parameter = 42.44 103 (R-h) Stress (psi) Larson-Miller parameter = Stress = 80 MPA Stress = 11.6 10³ psi
Transcribed Image Text:Stress (MPa) 100 10 25 x103 12 x103 T(20 + log t)(°R-h) 35 x103 30 x103 16 x103 40 45 x103 x103 24 x103 20 x103 T(20 + log t.)(K-h) 50 x103 28 x103 10,000 100,000 23.26. 10³ (K-h) 1000 Larson-Miller parameter = 42.44 103 (R-h) Stress (psi) Larson-Miller parameter = Stress = 80 MPA Stress = 11.6 10³ psi
For an 18-8 Mo stainless steel (Animated Figure 8.36), predict the time to rupture for a component that is subjected to a stress of 80 MPa (11,600 psi) at 700°C (973 K). ! hours
Transcribed Image Text:For an 18-8 Mo stainless steel (Animated Figure 8.36), predict the time to rupture for a component that is subjected to a stress of 80 MPa (11,600 psi) at 700°C (973 K). ! hours
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