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For a constant-pressure expansion of a gas, the work done by the system (-w) is equal to the pressure (P) multiplied by the change in volume (∆V) of the gas. Calculate the work done by a gas when it volume expands from 3.0 L to 8.0 L under atmospheric pressure. How much heat did it absorb if its energy did not change (i.e., ∆E =0)? Note : 1 L∙atm = 101.325 J

For a constant-pressure expansion of a gas, the work done by the system (-w) is equal to the pressure (P) multiplied by the change in volume (∆V) of the gas. Calculate the work done by a gas when it volume expands from 3.0 L to 8.0 L under atmospheric pressure. How much heat did it absorb if its energy did not change (i.e., ∆E =0)? Note : 1 L∙atm = 101.325 J

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For a constant-pressure expansion of a gas, the work done by the system (-w) is equal to the pressure (P) multiplied by the change in volume (∆V) of the gas. Calculate the work done by a gas when it volume expands from 3.0 L to 8.0 L under atmospheric pressure. How much heat did it absorb if its energy did not change (i.e., ∆E =0)?

Note : 1 L∙atm = 101.325 J

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