The combustion of toluene has a Arxn of -3.91 x 10³ kJ/mol. When 1.30 g of toluene (C7Hs) undergoes combustion in a bomb calorimeter, the temperature rises from 22.80 °C to 36.11 °C. Find the heat capacity of the bomb calorimeter. Express your answer using three significant figures. Ccal = [-] ΑΣΦ 3 → ? kJ/°C

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Chapter8: Thermochemistry
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The combustion of toluene has a \(\Delta E_{\text{rxn}}\) of \(-3.91 \times 10^3\) kJ/mol. When 1.30 g of toluene (\(C_7H_8\)) undergoes combustion in a bomb calorimeter, the temperature rises from 22.80 °C to 36.11 °C. Find the heat capacity of the bomb calorimeter.

**Express your answer using three significant figures.**

\[ C_{\text{cal}} = \, \, \, \, \, \] kJ/°C

This question includes a mathematical input field for the solution.
Transcribed Image Text:The combustion of toluene has a \(\Delta E_{\text{rxn}}\) of \(-3.91 \times 10^3\) kJ/mol. When 1.30 g of toluene (\(C_7H_8\)) undergoes combustion in a bomb calorimeter, the temperature rises from 22.80 °C to 36.11 °C. Find the heat capacity of the bomb calorimeter. **Express your answer using three significant figures.** \[ C_{\text{cal}} = \, \, \, \, \, \] kJ/°C This question includes a mathematical input field for the solution.
Expert Solution
Step 1: Determine the given values

increment E subscript r x n end subscript space equals space minus 3.91 space cross times 10 cubed space k J divided by m o l
M a s s space o f space t o l u e n e space left parenthesis C subscript 7 H subscript 8 right parenthesis space equals space 1.30 space g
I n i t i a l space t e m p e r a t u r e space equals space 22.80 to the power of o C
F i n a l space t e m p e r a t u r e space equals space 36.11 to the power of o C

W e space h a v e space t o space c a l c u l a t e space t h e space h e a t space c a p a c i t y space o f space t h e space b o m b space c a l o r i m e t e r. space

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