For a certain reaction, Kc�� = 9.80×10−10 and kf=�f= 2.59×10−5 M−2⋅s−1�−2⋅s−1 . Calculate the value of the reverse rate constant, kr�r, given that the reverse reaction is of the same molecularity as the forward reaction.Express your answer with the appropriate units. Include explicit multiplication within units, for example to enter M−2⋅s−1�−2⋅�−1 include ⋅⋅ (multiplication dot) between each measurement.View Available Hint(s) For a different reaction, Kc�� = 5.40×102, kf=8.96×103s−1�f=8.96×103s−1 , and kr=�r= 16.6 s−1s−1 . Adding a catalyst increases the forward rate constant to 2.05×106 s−1s−1 . What is the new value of the reverse reaction constant, kr�r, after adding catalyst?Express your answer with the appropriate units. Include explicit multiplication within units, for example to enter M−2⋅s−1�−2⋅�−1 include ⋅⋅ (multiplication dot) between each measurement.View Available Hint(s)

Answered: For a certain reaction, Kc�� =…

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 92QRT

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For a certain reaction, Kc�� = 9.80×10⁻¹⁰ and kf=�f= 2.59×10⁻⁵ M−2⋅s−1�−2⋅s−1 . Calculate the value of the reverse rate constant, kr�r, given that the reverse reaction is of the same molecularity as the forward reaction.

Express your answer with the appropriate units. Include explicit multiplication within units, for example to enter M−2⋅s−1�−2⋅�−1 include ⋅⋅ (multiplication dot) between each measurement.

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For a different reaction, Kc�� = 5.40×10², kf=8.96×103s−1�f=8.96×103s−1 , and kr=�r= 16.6 s−1s−1 . Adding a catalyst increases the forward rate constant to 2.05×10⁶ s−1s−1 . What is the new value of the reverse reaction constant, kr�r, after adding catalyst?

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