12.12 Following are the results of consolidated-undrained triaxial tests on undisturbedsoils retrieved from a 4-m-thick saturated clay layer in the field (ysat = 19 kN/m³).a. Estimate graphically the Mohr–Coulomb shear strength parameters c' and ø'.b. Estimate the shear strength in the middle of the clay layer.ChamberDeviator stress,pressure, o3(kN/m?)(Ar),(kN/m?)Pore pressure atfailure, (Aud,(kN/m?)Test no.1100170-15200260-403300360-80© Cengage Learning 2014

For the triaxial test the effective major and minor principal stresses at failure. Graphical…

Answered: Following are the results of…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A clay specimen with drained shear strength parameters of c'=5 kPa and Φ=320 is consolidated under all around pressure of 140 kPa.The specimen was then loaded axially to failure under undrained condition and failed when the principal stress diffrences reached 60 kPa.Calculate the pore pressure(u) and the pore pressure coefficient D(=A*B=Δu/Δσv) of the clay.
The results below were obtained at failure in a series of consolidated-untrained triaxial tests, with pore water pressure measurement, on specimens of a fully saturated clay. Determine the values of the shear strength parameters c' and 'If a specimen of the same soil were consolidated under an all-round pressure of 300 kN/m² and the principal stress difference applied with the all-round pressure changed to 400kN/m², what would be the expected value of principal stress difference at failure" 150 300 450 600 03 (kN/m²) 01-03 (kN/m²) u (kN/m²) 103 202 305 410 82 169 252 331
A normally consolidated soil was subjected to tri-axial test with the following data: cell pressure= 320 kPa; The specimen failed when the deviator stress is 460 kPa. Compute the shear stress in kPa on the failure plane. a.550 b.141.42 c.208.9 d.119.03
During a triaxial test, the porewater pressure at failure is 80 kPa. If the total normal stress is 245 kPa and the soil has a cohesion of 12 kPa and ø' of 30°. Q: What is the shear strength of the soil considering effective stress? Round off your answer to the whole number.
The angle of friction of a compacted dry sand is 37 degrees. In a direct shear test on the sand, anormal stress of 150 kN/m^2 was applied. The size of the specimen was 50mmx50mx30mm(height) SITUATION 1 a. Compute the shearing stress Your answer b. What shear force will cause shear failure? Your answer c. Determine the shear stress at a depth of 3m if the void ratio of the soil is 0.60. Gs Of sand is 2.70
A standard specimen of cohesionless sand was tested in triaxial compression test and the sample field at a deviator stress of 450 KN/ sq-m, when the cell pressure was 100 kN/sq-m under drained condition. Find the effective angle of shearing resistance of sand. what would be the deviator stress and the Major principle stress at the failure of another identical specimen of sand if it is tested under a cell pressure of 200 KN/ sq-m ?
A consolidated undrained triaxial test was performed on a normally consolidated clay with a critical state friction angle of 230. After an initial isotropic consolidation at a cell pressure of 50 kPa, drainage was turned off, the cell pressure was increased to 85 kPa, and the sample was loaded to ultimate conditions. A pore pressure of 55 kPa was measured at ultimate state. What value of major principal total stress was measured at the ultimate state?
A saturated specimen of cohesionless sand was tested under drained conditions in a triaxial compression test apparatus and the sample failed at a deviator stress of 482 kN/m2 and the plane of failure made an angle of 60⁰° with the horizontal. Find the magnitude of the principal minor stress in kPa at failure for identical specimen of sand if it is tested under a cell pressure of 200 kPa. Include fbd.
2. The results of a consolidated-drained triaxial test conducted on a normally consolidated clay are as follows: Chamber confining stress = 220 KPa Deviator stress at failure = 320 KPa (a) Angle of friction (b) Angle of failure (c) Normal and Shear stress on the failure plane Calculate:
A consolidated-undrained test determines that the shear strength of a normally consolidated clay is given by τf = σ’tan 27o. The confining pressure is 150 kPa, and deviator stress at failure is 120 kPa.• Find the consolidated-undrained friction angle• Pore water pressure developed in the specimen at failureFinal answer should be in 3 decimal places.
Q: A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as following: confining stress, G3 = 150 kN/m² and deviator stress, (Aod)t = 150 kN/m². i) Determine angle of friction, q; ii) Determine angle 0 that the failure plane makes with the major principal plane; iii) Find the normal stress and the shear stress ty on the failure plane; and iv) Determine the effective normal stress on the plane of maximum shear stress. Express your results in two decimal places.
c. An undisturbed soil sample, 110 mm in diameter and 220 mm in height, was tested in a triaxial machine. The sample sheared under an additional axial load of 3.35 kN with a vertical deformation of 21 mm. The failure plane was inclined at 50° to the horizontal and the cell pressure was 300 kN/m². i. Draw the Mohr circle diagram representing the above stress conditions, and from it determine: - Coulomb's equation for the shear strength of the soil, in terms of total stress; - the magnitude and obliquity of the resultant stress on the failure plane. ii. A further undisturbed sample of the soil was tested in a shear box under the same drainage conditions as used for the previous test. If the area of the box was 3600 mm² and the normal load was 500 N, what would you expect the failure stress to have been?

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