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Finding the basis of eigenstates of total spin S? = (S,? + S,? +S;?)?. You can first consider the total spin subspaces S,2 descomposes into 3+1. And then form the invariant subspaces of S² through (3 + 1) x 2 = 3 x 2 +1x 2 = 4 +2 + 2. %3D = (S,? + S2?)? , where 2x2 %3D

Finding the basis of eigenstates of total spin S? = (S,? + S,? +S;?)?. You can first consider the total spin subspaces S,2 descomposes into 3+1. And then form the invariant subspaces of S² through (3 + 1) x 2 = 3 x 2 +1x 2 = 4 +2 + 2. %3D = (S,? + S2?)? , where 2x2 %3D

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Finding the basis of eigenstates of total spin S? = (S,? + S,? + S,2)?. You can first consider the total spin subspaces S32 = (S,? + S2?)² , where 2x2 descomposes into 3+1. And then form the invariant subspaces of S? through (3 + 1) x 2 = 3 x 2 +1 x 2 = 4 + 2 + 2.
Transcribed Image Text:Finding the basis of eigenstates of total spin S? = (S,? + S,? + S,2)?. You can first consider the total spin subspaces S32 = (S,? + S2?)² , where 2x2 descomposes into 3+1. And then form the invariant subspaces of S? through (3 + 1) x 2 = 3 x 2 +1 x 2 = 4 + 2 + 2.
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