Q6) Find the ultimate compressive (Qu) and pullout (Tu) capacities of the driven closed-endsteel pipe-pile shown in Fig. (6). Given data:outer diameter = 610 mmweight of empty pipe = 186.8 kg/ma = 1 for cu ≤ 25 kPaぬ。343536Disp. Piles41.349.960.9Cu = 12 kN/m²Ysat = 16 kN/m³Cu = 50 kN/m²Ysat = 18 kN/m³c=0Cu = 100 kN/m²Ysat = 20 kN/m³= 35°Ysat = 20 kN/m³3wall thickness = 12.7 mmpile to be filled with concrete.α = 0.5 for c₂ ≥ 75 kPaNoNon-disp. PilesFig. (6)20.324.630.1W.T.-Ans.: Qu= 4165 kN, T₂ = 1696 kN6 m4.5 m4.5 m6 m

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Answered: Find the ultimate compressive (Qu) and…

Find the ultimate compressive (Qu) and pullout (Tu) capacities of the driven closed-end steel pipe-pile shown in Fig. (6). Given data:

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.

Question

Q6) Find the ultimate compressive (Qu) and pullout (Tu) capacities of the driven closed-end
steel pipe-pile shown in Fig. (6). Given data:
outer diameter = 610 mm
weight of empty pipe = 186.8 kg/m
a = 1 for cu ≤ 25 kPa
ぬ。
34
35
36
Disp. Piles
41.3
49.9
60.9
Cu = 12 kN/m²
Ysat = 16 kN/m³
Cu = 50 kN/m²
Ysat = 18 kN/m³
c=0
Cu = 100 kN/m²
Ysat = 20 kN/m³
= 35°
Ysat = 20 kN/m³
3
wall thickness = 12.7 mm
pile to be filled with concrete.
α = 0.5 for c₂ ≥ 75 kPa
No
Non-disp. Piles
Fig. (6)
20.3
24.6
30.1
W.T.
-
Ans.: Qu= 4165 kN, T₂ = 1696 kN
6 m
4.5 m
4.5 m
6 m

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