Find the regression equation, letting overhead width be the predictor (x) variable. Find the best predicted weight of a seal if the overhead width measured from a photograph is 2 cm. Can the prediction be correct? What is wrong with predicting the weight in this case? Use a significance level of 0.05. Overhead Width (cm) 8.2 7.9 9.2 9.4 9.9 7.6 Weight (kg) 154 172 219 201 242 157 Click the icon to view the critical values of the Pearson correlation coefficient r. The regression equation is y =D+Dx. (Round to one decimal place as needed.) The best predicted weight for an overhead width of 2 cm is (Round to one decimal place as needed.) Can the prediction be correct? What is wrong with predicting the weight in this case? O A. The prediction cannot be correct because a negative weight does not make sense. The width in this case is beyond the scope of the available sample data. O B. The prediction cannot be correct because there is not sufficient evidence of a linear correlation. The width in this case is beyond the scope of the available sample data. OC. The prediction cannot be correct because a negative weight does not make sense and because there is not sufficient evidence of a linear correlation. O D. The prediction can be correct. There is nothing wrong with predicting the weight in this case.
Find the regression equation, letting overhead width be the predictor (x) variable. Find the best predicted weight of a seal if the overhead width measured from a photograph is 2 cm. Can the prediction be correct? What is wrong with predicting the weight in this case? Use a significance level of 0.05. Overhead Width (cm) 8.2 7.9 9.2 9.4 9.9 7.6 Weight (kg) 154 172 219 201 242 157 Click the icon to view the critical values of the Pearson correlation coefficient r. The regression equation is y =D+Dx. (Round to one decimal place as needed.) The best predicted weight for an overhead width of 2 cm is (Round to one decimal place as needed.) Can the prediction be correct? What is wrong with predicting the weight in this case? O A. The prediction cannot be correct because a negative weight does not make sense. The width in this case is beyond the scope of the available sample data. O B. The prediction cannot be correct because there is not sufficient evidence of a linear correlation. The width in this case is beyond the scope of the available sample data. OC. The prediction cannot be correct because a negative weight does not make sense and because there is not sufficient evidence of a linear correlation. O D. The prediction can be correct. There is nothing wrong with predicting the weight in this case.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Find the regression equation, letting overhead width be the predictor (x) variable. Find the best predicted weight of a seal if the overhead width measured from a photograph is 2cm. Can the prediction be correct? What is wrong with predicting the weight in this case? Use a significance level of 0.05.
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