Please help solve. prediction be correct? What is vFind the regression equation, letting overhead width be the predictor (x) varwith predicting the weight in this case? Use a significance level of 0.05.Critical Values of the Pearson Correlation CoefficientrOverhead Width (cm)7.78.18.99.77.2Weight (kg)150196224232148Click the icon to view the critical values of the Pearson correlation coeCritical Values of the Pearson Correlation Coefficient ra = 0.010.9900.9590.9170.8750.8340.7980.7650.735NOTE: To test H,: p= 0against H,: p 0, reject H,lif the absolute value of r isgreater than the criticalvalue in the table.a = 0.050.950T0.8780.8110.7540.7070.66610.6320.6020.5760.5530.5320.5140.4970.4820.4680.4560.4440.396InThe regression equation is y =+x.(Round to one decimal place as needed.)The best predicted weight for an overhead width of 1.8 cm is kg.(Round to one decimal place as needed.)9101112Can the prediction be correct? What is wrong with predicting the weight in t.708O A. The prediction cannot be correct because a negative weight does n0.6840.6610.6410.6230.6060.5900.5750.5610.50513O B. The prediction cannot be correct because there is not sufficient evid1415161718192025OC. The prediction cannot be correct because a negative weight does nO D. The prediction can be correct. There is nothing wrong with predictin Find the regression equation, letting overhead width be the predictor (x) variable. Find the best predicted weight of a seal if the overhead width measured from a photograph is 1.8 cm. Can the prediction be correct? What is wrongwith predicting the weight in this case? Use a significance level of 0.05.Overhead Width (cm)7.78.18.99.77.28.2Weight (kg)150196224232148196E Click the icon to view the critical values of the Pearson correlation coefficient r.....The regression equation is y =+ x.(Round to one decimal place as needed.)The best predicted weight for an overhead width of 1.8 cm is kg.(Round to one decimal place as needed.)Can the prediction be correct? What is wrong with predicting the weight in this case?O A. The prediction cannot be correct because a negative weight does not make sense. The width in this case is beyond the scope of the available sample data.O B. The prediction cannot be correct because there is not sufficient evidence of a linear correlation. The width in this case is beyond the scope of the available sample data.O C. The prediction cannot be correct because a negative weight does not make sense and because there is not sufficient evidence of a linear correlation.O D. The prediction can be correct. There is nothing wrong with predicting the weight in this case.

Name: Please help solve. prediction be correct? What is vFind the regression
Uploaded: 2024-03-20T06:46:03.000Z
Channel: Bartleby
Description: Please help solve. prediction be correct? What is vFind the regression equation, letting overhead width be the predictor (x) varwith predicting the weight in this case? Use a significance level of 0.05.Critical Values of the Pearson Correlation Coeff