Find the regression equation, letting the diameter be the predictor (x) variable. Find the best predicted circumference of a beachball with a diameter of 41.3 cm. How does the result compare to the actual circumference of 129.7 cm? Use Baseball Basketball Golf Soccer Tennis Ping-Pong Volleyball 21.3 Diameter 7.3 Circumference 22.9 24.2 4.3 21.6 7.1 76.0 13.5 67.9 22.3 3.9 12.3 66.9 Click the icon to view the critical values of the Pearson correlation coefficient r. The regression equation is y=+x. (Round to five decimal places as needed.) The best predicted circumference for a diameter of 41.3 cm is cm. (Round to one decimal place as needed.) How does the result compare to the actual circumference of 129.7 cm? Critical Values of the Pearson Correlation Coefficie 15 16 Critical Values of the Pearson Correlation Coefficient r = 0.01 -0.05 0.990 0.959 0.917 0.875 0.834 0.950 0.878 0.811 0.754 0.707 NOTE: To test H against H,: p#0 if the absolute v greater than the value in the tabl

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Author:Amos Gilat
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Question
Find the regression equation, letting the diameter be the predictor (x) variable. Find the best predicted circumference of a beachball with a diameter of 41.3 cm. How does the result compare to the actual circumference of 129.7 cm? Use a significance level of 0.05.
Baseball Basketball Golf Soccer Tennis Ping-Pong Volleyball
Diameter
7.3 24.2 4.3 21.6 7.1 3.9 21.3
Circumference 22.9 76.0 13.5 67.9 22.3
12.3
66.9
Click the icon to view the critical values of the Pearson correlation coefficient r.
The regression equation is ŷ =+x.
(Round to five decimal places as needed.)
The best predicted circumference for a diameter of 41.3 cm is
(Round to one decimal place as needed.)
How does the result compare to the actual circumference of 129.7 cm?
cm.
O A. Even though 41.3 cm is beyond the scope of the sample diameters, the predicted value yields the actual circumference.
O B. Even though 41.3 cm is within the scope of the sample diameters, the predicted value yields a very different circumference.
O C. Since 41.3 cm is within the scope of the sample diameters, the predicted value yields the actual circumference.
O D. Since 41.3 cm is beyond the scope of the sample diameters, the predicted value yields a very different circumference.
(...)
Critical Values of the Pearson Correlation Coefficient r
In
14
15
16
7
18
19
10
11
12
13
14
15
16
17
18
19
20
25
30
135
40
45
50
60
170
180
90
100
ון
n
Critical Values of the Pearson Correlation Coefficient r
α = 0.05
α = 0.01
0.950
0.878
0.811
0.754
0.707
0.666
0.632
10.602
10.576
10.553
0.532
0.514
0.497
0.482
0.468
0.456
10.444
0.396
10.361
10.335
0.312
0.294
0.279
0.254
10.236
0.220
0.207
0.196
-0.05
0.990
0.959
0.917
0.875
0.834
0.798
10.765
0.735
10.708
0.684
0.661
0.641
0.623
0.606
0.590
0.575
0.561
0.505
10.463
0.430
0.402
0.378
0.361
0.330
0.305
0.286
0.269
0.256
-0.01
NOTE: To test H₁: p=0
against H₁: p0, reject Ho
if the absolute value of r is
greater than the critical
value in the table.
- X
Transcribed Image Text:Find the regression equation, letting the diameter be the predictor (x) variable. Find the best predicted circumference of a beachball with a diameter of 41.3 cm. How does the result compare to the actual circumference of 129.7 cm? Use a significance level of 0.05. Baseball Basketball Golf Soccer Tennis Ping-Pong Volleyball Diameter 7.3 24.2 4.3 21.6 7.1 3.9 21.3 Circumference 22.9 76.0 13.5 67.9 22.3 12.3 66.9 Click the icon to view the critical values of the Pearson correlation coefficient r. The regression equation is ŷ =+x. (Round to five decimal places as needed.) The best predicted circumference for a diameter of 41.3 cm is (Round to one decimal place as needed.) How does the result compare to the actual circumference of 129.7 cm? cm. O A. Even though 41.3 cm is beyond the scope of the sample diameters, the predicted value yields the actual circumference. O B. Even though 41.3 cm is within the scope of the sample diameters, the predicted value yields a very different circumference. O C. Since 41.3 cm is within the scope of the sample diameters, the predicted value yields the actual circumference. O D. Since 41.3 cm is beyond the scope of the sample diameters, the predicted value yields a very different circumference. (...) Critical Values of the Pearson Correlation Coefficient r In 14 15 16 7 18 19 10 11 12 13 14 15 16 17 18 19 20 25 30 135 40 45 50 60 170 180 90 100 ון n Critical Values of the Pearson Correlation Coefficient r α = 0.05 α = 0.01 0.950 0.878 0.811 0.754 0.707 0.666 0.632 10.602 10.576 10.553 0.532 0.514 0.497 0.482 0.468 0.456 10.444 0.396 10.361 10.335 0.312 0.294 0.279 0.254 10.236 0.220 0.207 0.196 -0.05 0.990 0.959 0.917 0.875 0.834 0.798 10.765 0.735 10.708 0.684 0.661 0.641 0.623 0.606 0.590 0.575 0.561 0.505 10.463 0.430 0.402 0.378 0.361 0.330 0.305 0.286 0.269 0.256 -0.01 NOTE: To test H₁: p=0 against H₁: p0, reject Ho if the absolute value of r is greater than the critical value in the table. - X
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