find the raegents necessary **Title: Identifying Reagents for Organic Reactions****Image Description:**The image illustrates a sequence of organic reactions that require the identification of necessary reagents to achieve the desired transformations. The sequence consists of the following steps:1. **First Reaction:** - **Reactant:** A cyclohexane ring with a bromine atom attached (bromocyclohexane). - **Transformation:** The goal is to convert the bromocyclohexane to a cyclohexene by eliminating the bromine atom and forming a double bond. - **Product:** A cyclohexene (cyclohexane with one double bond). **Reaction Type:** This is a dehydrohalogenation reaction where the bromide is removed, resulting in the formation of a double bond.2. **Second Reaction:** - **Reactant:** The product from the first reaction, cyclohexene. - **Transformation:** The objective is to transform the cyclohexene into a linear compound with two aldehyde groups. - **Product:** A molecule with the structure of O=CH-(CH2)4-CHO, which is a six-carbon chain with an oxygen double-bonded to each end carbon (hexan-1,6-dial). **Reaction Type:** This is possibly an oxidative cleavage reaction, typically achieved using strong oxidizing agents to cleave the double bond and introduce carbonyl groups at the cleavage site.**Details:**- The arrows (???) indicate that the specific reagents needed for each transformation are not listed. This is a common exercise in organic chemistry, where students must determine which reagents will effectively facilitate each step in the reaction pathway.**Discussion Points for an Educational Setting:**- **Dehydrohalogenation:** Discuss the typical reagents used, such as a strong base like sodium hydroxide (NaOH) or potassium hydroxide (KOH), to promote the elimination reaction and create the double bond. - **Oxidative Cleavage:** Explain potential reagents like ozone (O3) followed by a reducing agent such as zinc (Zn) or dimethyl sulfide (DMS), which could be used for cleaving the double bond and forming aldehydes or ketones.This type of exercise aids in understanding reaction mechanisms and the role of different reagents in transforming organic molecules.

The given reaction complete in two steps. In the first step, the alkyl halide gives an elimination reaction in presence of a strong base, and in the second step, the alkene gives an ozonolysis reaction.Elimination reaction of alkyl halide: Alkyl halide gives an elimination reaction by reacting with a strong base. E2 reaction involves a one-step mechanism in which carbon-hydrogen and carbon-halogen bonds break to form a double bond (C=C Pi bond). The E2 reaction is a single step elimination, with a single transition state. The reaction follows second-order kinetics and the rate reaction depends on both the alkyl halide and the base (bimolecular). Zaitsev's rule predicts that in an elimination reaction, the most substituted product will be the most stable, and therefore the most favored. The given alkyl halide reacts with sodium ethoxide in ethanol solvent to give the alkene.Ozonolysis of alkene: In the ozonolysis reaction, the carbon-carbon bond of alkene has been replaced by a carbonyl group. Alkenes can be oxidized with ozone to form alcohols, aldehydes or ketones, or carboxylic acids. In this reaction, ozone is bubbled through a solution of the alkene in methanol at −78 °C. The ozonide formed in this can be reduced into a carbonyl compound when it reacts with dimethyl sulfide. The reaction is given below: