Question 15 (10 points) The Ka of benzoic acid, C6H5COOH is 6.30 x 105. The equation for the K₂ is: C6H5COOH (aq) + H₂O(1) C6H5COO (aq) + H30* (aq) a) What is the [H3O+] and [OH] in a 1.25 M solution? b) What is the pH and pOH of the solution? c) What are the equilibrium concentrations of H3O*, C6H5COOH, and C6H5COO

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Question 15 (10 points)
The Ka of benzoic acid, C6H5COOH is 6.30 x 10-5. The equation for the K₂ is:
C6H5COOH (aq) + H₂O(1) C6H5COO (aq) + H30* (aq)
a) What is the [H3O+] and [OH-] in a 1.25 M solution?
b) What is the pH and pOH of the solution?
c) What are the equilibrium
concentrations of H3O+, C6H5COOH, and C6H5COO
►ll
+ v
***
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Paragraph V B
I U A
Transcribed Image Text:Question 15 (10 points) The Ka of benzoic acid, C6H5COOH is 6.30 x 10-5. The equation for the K₂ is: C6H5COOH (aq) + H₂O(1) C6H5COO (aq) + H30* (aq) a) What is the [H3O+] and [OH-] in a 1.25 M solution? b) What is the pH and pOH of the solution? c) What are the equilibrium concentrations of H3O+, C6H5COOH, and C6H5COO ►ll + v *** X Paragraph V B I U A
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