Find the neutron separation energy of 'Li
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- Malignant tumors are commonlytreated with targeted x-ray radiation therapy. To generate these medicalx rays, a linear accelerator directs a high-energy beam of electronstoward a metal target—typically tungsten. As they near the tungsten nuclei,the electrons are deflected and accelerated, emitting high-energyphotons via bremsstrahlung. The resulting x rays are collimated into abeam that is directed at the tumor. The photons can deposit energy inthe tumor through Compton and photoelectric interactions. A typicaltumor has 108 cells/cm3, and in a full treatment, 4 MeV photons mayproduce a dose of 70 Gy in 35 fractional exposures on different days.The gray (Gy) is a measure of the absorbed energy dose of radiation perunit mass of tissue: 1 Gy = 1 J/kg. How much energy is imparted to one cell during one day’s treatment? Assume that the specific gravity of the tumor is 1 and that 1 J = 6 * 1018 eV. (a) 120 keV; (b) 12 MeV; (c) 120 MeV; (d) 120 * 103 MeV.An antimuon with 1000 MeV total energy crosses a 10 cm long silicon target. Calculate the energy loss.Calculate n initial for the wavelength 486.1nm the n final is 4 also calculate the energy emitted by the photon
- Find the proton separation energy and the neutron separa- tion energy of 125 TeCalculate the neutron separation energy for ¹25 Te.If the incident neutron with 6 Å wavelength hits a sample, and is scattered away with the scattering angle, 0=60 degree. 1) vector transfer, Q. If this is an elastic scattering event, please calculate the magnitude of the wave 2) If the scattered neutron loses energy with AE = E, – E, = -1 meV, please %3D %3D calculate the magnitude of the wave vector transfer, Q. 3) calculate the magnitude of the wave vector transfer, Q. If the scattered neutron gains energy with AE = E - E = 10 meV, please