Answered: A fraction of the 42.5 pm beam strikes… | bartleby

Related questions

Question

A fraction of the 42.5 pm beam strikes free elections at rest and it scattered at an angle of 35 from its original direction. what is the wavelength of the scattered protons? find the kinetic energy and momentum(both magnitude and direction) of the recoil electron.

Expert Solution

Step by step

Solved in 6 steps with 6 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

2. Protons with energy 1.0MeV scatter off a fixed spherical potential whose range is known to be a = 10-¹3 cm. The total elastic scattering cross section o and the differential cross section do/d are measured to a precision of about one percent. (a) Assuming that the energy is not near any resonance of the potential, show that the only phase shifts that can be reliably determined from the data are do and 6₁. (b) Given the experimental value o = = (10.5 ± 0.1) × 10-26 cm² and the values for do/dn listed in the table (one percent accuracy), determine do and 8₁. (Do not worry about the errors in your values for do or $₁. (deg) | dold_2 (10-26 cm²) O 1.232 45 90 135 180 1.103 0.823 0.585 0.499
Make a graph of laser energy vs. the kinetic energy of the ejected electrons from your data in the data table. Include a couple of the higher wavelength values that you observed in step 9. Graph the laser energy in *10-19 Joules on the x-axis and the electron kinetic energy in *10-19 Joules on the y-axis.
What is the maximum velocity of electrons ejected from a material by 61 nm photons, if they are bound to the material by 4.79 eV?
A particle is confined in a box of length L. The momentum is quantized and we find that the lowest possible value of the momentum for a particle in that box is 1.3 E-24 kg.m2/s. What is the length of the box? Express your answer in Angstroms (1E-10 m)
Problem 9: Rutherford Scattering A gold foil (5.9×1022 atoms/cm³) of "hair" thickness 80 µm is used in a Rutherford experiment to scatter a particles with energy 5 MeV. Find the fraction of particles scattered at angles 0 > 30°.
Electrons are fired at a rectangular potential energy barrier, once every 149 ms. If the barrier is 2.55 nm thick and has a height that exceeds the energy of the incident electrons by exactly 712 meV, how long on average would you expect to wait for one electron to pass through the barrier? 8.57 x105 average wait: Incorrect
Mehul
What wavelength of light is shining on a metal with work function ?=2.8??, if the stopping potential for the photocurrent (ejected electrons) is 5??