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Using the Thomson model, estimate the average scatter- ing angle when alpha particles (z = 2) with kinetic energy 3 MeV are scattered from gold (Z = 79). The atomic radius of gold is 0.179 nm.

Using the Thomson model, estimate the average scatter- ing angle when alpha particles (z = 2) with kinetic energy 3 MeV are scattered from gold (Z = 79). The atomic radius of gold is 0.179 nm.

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Using the Thomson model, estimate the average scatter- ing angle when alpha particles (z = 2) with kinetic energy 3 MeV are scattered from gold (Z = 79). The atomic radius of gold is 0.179 nm.
Transcribed Image Text:Using the Thomson model, estimate the average scatter- ing angle when alpha particles (z = 2) with kinetic energy 3 MeV are scattered from gold (Z = 79). The atomic radius of gold is 0.179 nm.
Expert Solution
Concept and Principle:
  • As per Thomson's model of the atom, an atom is a positive sphere with electrons embedded in it. There will be Z electrons and the total positive charge will be Ze.

 

  • The scattering angle of a positively charged particle getting close to an atom is given by,

θavg=14(e24πε0)(zZRK)

Here e is the charge of an electron, ε0 is the vacuum permittivity, z is the atomic number of the projectile, Z is the atomic number of the target, R is the radius of the nucleus, and K is the kinetic energy of the projectile.

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