Find the Binding energy per nucleon for 12050 Sn. Mass of proton mp = 1.00783 U, mass of neutron mn = 1.00867 U and mass of tin nucleus mSn = 119.902199 U. (take 1U = 931 MeV) 1) 8.0 MeV 2) 9.0 MeV 3) 7.5 MeV 4) 8.5 MeV

Find the Binding energy per nucleon for 12050 Sn. Mass of proton mp = 1.00783 U, mass of neutron mn = 1.00867 U and mass of tin nucleus mSn = 119.902199 U. (take 1U = 931 MeV) 1) 8.0 MeV 2) 9.0 MeV 3) 7.5 MeV 4) 8.5 MeV

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Question

Find the Binding energy per nucleon for ¹²⁰₅₀Sn. Mass of proton m_p = 1.00783 U, mass of neutron m_n = 1.00867 U and mass of tin nucleus m_Sn = 119.902199 U. (take 1U = 931 MeV)

1) 8.0 MeV

2) 9.0 MeV

3) 7.5 MeV

4) 8.5 MeV

Expert Solution