Find the Binding energy per nucleon for 12050 Sn. Mass of proton mp = 1.00783 U, mass of neutron mn = 1.00867 U and mass of tin nucleus mSn = 119.902199 U. (take 1U = 931 MeV) 1) 8.0 MeV 2) 9.0 MeV 3) 7.5 MeV 4) 8.5 MeV
Find the Binding energy per nucleon for 12050 Sn. Mass of proton mp = 1.00783 U, mass of neutron mn = 1.00867 U and mass of tin nucleus mSn = 119.902199 U. (take 1U = 931 MeV) 1) 8.0 MeV 2) 9.0 MeV 3) 7.5 MeV 4) 8.5 MeV
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Find the Binding energy per nucleon for 12050 Sn. Mass of proton mp = 1.00783 U, mass of neutron mn = 1.00867 U and mass of tin nucleus mSn = 119.902199 U. (take 1U = 931 MeV)
1) 8.0 MeV
2) 9.0 MeV
3) 7.5 MeV
4) 8.5 MeV
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