fI 0.000 01.4946 1KHZ tEOL T'D UPP1) = 9.28U Fres)=1.488IHZ Upr(2) = 1.98U 5.000 CH2 1.000 Time 200.Qus 0+8.0000s From the picture is the electrical signal that measures across the resistor and inductor. Calculate the impedance (Z) of the RL series circuit. Given that CH1 is the yellow line (Vpp = 9.20 V), CH 2 is the blue line (Vpp = 1.92 V), R = 1,000 ohms and Z = VR? + (X, – Xc)² (answer only the number in ohm)

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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f0 0.000
01.4946 1KHZ
IGOL T'D
UPP1) = 9.28U
Fres)=1.488IHZ UPr(2) = 1.98U
CH2 1.000
Time 200.Qus 0+8.0000s
From the picture is the electrical signal that measures across the resistor and inductor.
Calculate the impedance (Z) of the RL series circuit. Given that CH1 is the yellow line (Vpp
= 9.20 V), CH 2 is the blue line (Vpp = 1.92 V), R = 1,000 ohms and
Z = VR? + (XL – Xc)²
(answer only the number in ohm)
Transcribed Image Text:f0 0.000 01.4946 1KHZ IGOL T'D UPP1) = 9.28U Fres)=1.488IHZ UPr(2) = 1.98U CH2 1.000 Time 200.Qus 0+8.0000s From the picture is the electrical signal that measures across the resistor and inductor. Calculate the impedance (Z) of the RL series circuit. Given that CH1 is the yellow line (Vpp = 9.20 V), CH 2 is the blue line (Vpp = 1.92 V), R = 1,000 ohms and Z = VR? + (XL – Xc)² (answer only the number in ohm)
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