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Given R1=150, R2=18 Q, R3 = 4 Q2, and L = 4 H, for the circuit shown in the figure shown below, determine the output current, i (t). Assuming an output current in the form i。 (t) = K₁ + K₂e, enter the value of K₂ in mA. 12 V +1 m R1Ω = 0 www LH R20 + 6V R302 i(t)

Given R1=150, R2=18 Q, R3 = 4 Q2, and L = 4 H, for the circuit shown in the figure shown below, determine the output current, i (t). Assuming an output current in the form i。 (t) = K₁ + K₂e, enter the value of K₂ in mA. 12 V +1 m R1Ω = 0 www LH R20 + 6V R302 i(t)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Can you please help me with this one? The answer is NOT 168mA, and the previous help requested gave me an incorrect answer. Please be careful with signs.

 

 

Please answer in typing format please ASAP

 

Given R1=150, R2=18 Q, R3 = 4 Q, and L = 4 H, for the circuit shown in the figure shown below, determine the output current, i (t). Assuming an output current in the form i. (t) = K₁ + K₂e, enter the value of K₂ in mA. 12 V (+ ww R1Ω ● t = 0 of LH R20 + 6 V R30 i(t) THE VALUES IN THIS PROBLEM MAY NOT MATCH THE PREVIOUS PROBLEM! Notes on entering solution: • Enter your solution as a whole number in mA • Do not include units in your answer • ex. 5 mA is entered as 5.00 Pay attention to signs
Transcribed Image Text:Given R1=150, R2=18 Q, R3 = 4 Q, and L = 4 H, for the circuit shown in the figure shown below, determine the output current, i (t). Assuming an output current in the form i. (t) = K₁ + K₂e, enter the value of K₂ in mA. 12 V (+ ww R1Ω ● t = 0 of LH R20 + 6 V R30 i(t) THE VALUES IN THIS PROBLEM MAY NOT MATCH THE PREVIOUS PROBLEM! Notes on entering solution: • Enter your solution as a whole number in mA • Do not include units in your answer • ex. 5 mA is entered as 5.00 Pay attention to signs
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