_ C0=1, C1=1 B0=1, B1=1 D3 CO=1, C1=0 D2 12 B0=1, B1=0 CO=0, C1=1 D1 B0=0, B1=1 C0=0, C1=0 DO 80 C A B F2 8-bit ALU Figure 1: 8-bit data-path FO F2 F1 FO Functionality 0 0 0 ADD the value on the A bus to the value on the B bus 0 0 1 AND the value on the A bus to the value on the B bus 0 1 0 0 1 1 LEFT SHIFT the value on the B bus by the number of bits specified on the A bus RIGHT SHIFT the value on the B bus by the number of bits specified on the A bus INCREMENT the value on the A bus by 1 1 0 0 1 0 1 IF DO = 1 THEN B ELSE O 1 1 0 SET output of the ALU to 0 1 1 1 SET the output of the ALU to the value on the B bus Table 1: ALU functions
_ C0=1, C1=1 B0=1, B1=1 D3 CO=1, C1=0 D2 12 B0=1, B1=0 CO=0, C1=1 D1 B0=0, B1=1 C0=0, C1=0 DO 80 C A B F2 8-bit ALU Figure 1: 8-bit data-path FO F2 F1 FO Functionality 0 0 0 ADD the value on the A bus to the value on the B bus 0 0 1 AND the value on the A bus to the value on the B bus 0 1 0 0 1 1 LEFT SHIFT the value on the B bus by the number of bits specified on the A bus RIGHT SHIFT the value on the B bus by the number of bits specified on the A bus INCREMENT the value on the A bus by 1 1 0 0 1 0 1 IF DO = 1 THEN B ELSE O 1 1 0 SET output of the ALU to 0 1 1 1 SET the output of the ALU to the value on the B bus Table 1: ALU functions
Computer Networking: A Top-Down Approach (7th Edition)
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ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
Related questions
Question
Using Logism Softwarel The most important and possible most difficult component to implement is the 8 bit arithmetic logic unit. The
functions of the ALU are shown in Table 1. The ALU should have 5 inputs (A-input, B-input, F0-input, F1-input, Finput) and 1 output (C-output). You will need to determine how many bits each input and output should have.
Remember, you are designing an 8-bit microprocessor! . For example, to add the value on the A-bus
8-bit ALU
to the value on the B-bus, you can simply use an 8-bit adder. Explore the components in Logisim! Additionally,
you can think about using a multiplexer to determine which ALU function will be performed

Transcribed Image Text:_ C0=1, C1=1
B0=1, B1=1
D3
CO=1, C1=0
D2
12
B0=1, B1=0
CO=0, C1=1
D1
B0=0, B1=1
C0=0, C1=0
DO
80
C
A
B
F2
8-bit ALU
Figure 1: 8-bit data-path
FO

Transcribed Image Text:F2
F1
FO
Functionality
0
0
0
ADD the value on the A bus to the value on the B bus
0
0
1
AND the value on the A bus to the value on the B bus
0
1
0
0
1
1
LEFT SHIFT the value on the B bus by the number of bits specified on
the A bus
RIGHT SHIFT the value on the B bus by the number of bits specified on
the A bus
INCREMENT the value on the A bus by 1
1
0
0
1
0
1
IF DO = 1 THEN B ELSE O
1
1
0 SET output of the ALU to 0
1
1
1
SET the output of the ALU to the value on the B bus
Table 1: ALU functions
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