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Opcode 000 001 010 011 100 101 110 111 Operation O=B O=A^ B (bitwise xor) O=A AND B (bitwise and) O=A OR B (bitwise or) O= A + B (addition) O= A - B (subtract) O(7) = 0, 0(6:0) = B (7:1) (logical shift right) O=AB (multiplication) Description Output is equal to input B - Xor of each bit in A with the corresponding bit in B AND of each bit in A with the corresponding bit in B OR of each bit in A with the corresponding bit in B 8 bit addition with a final carry out bit 8 bit subtraction with a borrow out bit Logical shift of the data at input B right by one bit 8 Multiplication. To make our design simpler, we will only keep the lower 8 bits of the result and signal an overflow

Opcode 000 001 010 011 100 101 110 111 Operation O=B O=A^ B (bitwise xor) O=A AND B (bitwise and) O=A OR B (bitwise or) O= A + B (addition) O= A - B (subtract) O(7) = 0, 0(6:0) = B (7:1) (logical shift right) O=AB (multiplication) Description Output is equal to input B - Xor of each bit in A with the corresponding bit in B AND of each bit in A with the corresponding bit in B OR of each bit in A with the corresponding bit in B 8 bit addition with a final carry out bit 8 bit subtraction with a borrow out bit Logical shift of the data at input B right by one bit 8 Multiplication. To make our design simpler, we will only keep the lower 8 bits of the result and signal an overflow

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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please help me with the multiplication part. How can I create the 8 bit multiplier circuit using logic gate? We know that the input for A: 10101010 , input for B: 10101010. Thank you very much
Opcode 000 001 010 011 100 101 110 111 Operation O=B O=AB (bitwise xor) O=A AND B (bitwise and) O=A OR B (bitwise or) O = A + B (addition) O = A - B (subtract) O(7) = 0, 0(6:0) = B (7:1) (logical shift right) O=AB (multiplication) Description Output is equal to input B - Xor of each bit in A with the corresponding bit in B AND of each bit in A with the corresponding bit in B OR of each bit in A with the corresponding bit in B 8 bit addition with a final carry out bit 8 bit subtraction with a borrow out bit Logical shift of the data at input B right by one bit 8 Multiplication. To make our design simpler, we will only keep the lower 8 bits of the result and signal an overflow
Transcribed Image Text:Opcode 000 001 010 011 100 101 110 111 Operation O=B O=AB (bitwise xor) O=A AND B (bitwise and) O=A OR B (bitwise or) O = A + B (addition) O = A - B (subtract) O(7) = 0, 0(6:0) = B (7:1) (logical shift right) O=AB (multiplication) Description Output is equal to input B - Xor of each bit in A with the corresponding bit in B AND of each bit in A with the corresponding bit in B OR of each bit in A with the corresponding bit in B 8 bit addition with a final carry out bit 8 bit subtraction with a borrow out bit Logical shift of the data at input B right by one bit 8 Multiplication. To make our design simpler, we will only keep the lower 8 bits of the result and signal an overflow
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