Explain what would happen to the length of the interval if the confidence level were decreased to 95%.
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A: Hypothesized mean µ = 44 minutes Sample size (n) = 51 Mean x̅ = 47.8 minutes Standard deviation (s)…
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Q: It currently takes users a mean of 13 minutes to install the most popular computer program made by…
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Q: The U.S. Center for Disease Control reports that the mean life expectancy was 47.6 years for whites…
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Q: It currently takes users a mean of 37 minutes to install the most popular computer program made by…
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Q: It currently takes users a mean of 3232 minutes to install the most popular computer program made by…
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Q: It currently takes users a mean of 44 minutes to insta made to the program, the company executives…
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In a recent year, a sample of the South American Redeye Piranha was collected by fishermen on a particular river. Wildlife biologists regard this sample as a random sample of all Redeye Piranha in that river. The mean length of the 60 fish in the sample was 12.88 cm, and a 99% confidence level for the true mean length of all Redeye Piranha in that river is 12.09 cm to 13.67 cm.
Explain what would happen to the length of the interval if the confidence level were decreased to 95%.
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- The U.S. Center for Disease Control reports that in year 1900, the mean life expectancy is 47.6 years for whites and 33 years for nonwhites. (Click here for reference data) Suppose a survey of randomly selected death records for white and nonwhite people born in 1900 from a certain county is conducted. Of the 110 whites surveyed, the mean life span was 48.2 years with a standard deviation of 11.2 years and of the 95 nonwhites, the mean life span was 39.3 years with a standard deviation of 16 years. Conduct a hypothesis test at the 0.05 level of significance to determine whether there was no difference in mean life spans in the county for whites and nonwhites in year 1900. Preliminary: Is it safe to assume thatnw≤5% of all white people born in 1900 andnnw≤5% of all nonwhite people born in 1900? No Yes Is nw≥30 and nnw≥30 ? No Yes Test the claim: Determine the null and alternative hypotheses. H0: μw μnw Ha: μw μnw Determine the test statistic. Round to four…A certain type of battery supercharger was found to take a mean of 15.4 minutes to charge a standard electric vehicle (EV) battery. A firmware update for this type of supercharger was recently released, but the update has received negative reviews from users. A researcher suspects the mean time the updated superchargers take to charge a standard EV battery is greater than 15.4 minutes. To test his claim, he chooses 15 of the updated superchargers at random and measures the time it takes each one to charge a standard EV battery. He finds that the superchargers take a sample mean of 16.1 minutes to charge a standard EV battery, with a sample standard deviation of 1.8 minutes. Assume that the population of amounts of time to charge a standard EV battery using the updated superchargers is approximately normally distributed. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.05 level of significance, to support the claim that u, the mean time…A nationwide job recruiting firm wants to compare the annual incomes for childcare workers in Utah and Oregon. Due to recent trends in the childcare industry, the firm suspects that the mean annual income of childcare workers in Utah is less than the mean annual income of childcare workers in Oregon. To see if this is true, the firm selected a random sample of 20 childcare workers from Utah and an independent random sample of 20 childcare workers from Oregon and asked them to report their mean annual income. The data obtained were as follows. Annual income in dollars 27060 , 42320 , 36445 , 37895, 44564 , 35325 , 30313 , 28698, 33706 , 48365 , 26946 , 25063 , 28339 , 29265 , 40051 , 37026 , 40150 , 42753 , 27820, 39471 Utah 29769 , 48859 , 32480 , 36288,45102 , 46219 ,51098 , 45516 , 38834 , 44659 , 40755 , 38006 , 39947 , 29801 , 32200, 38731 , 41370 , 28059 , 33753 , 35271 Oregon Send data to calc... v Send data to Excel The population standard deviation for the annual incomes of…
- A study was conducted to investigate the effect of a new drug on blood pressure. A sample of 25 patients was randomly selected and their blood pressure was measured both before and after taking the drug. The sample mean blood pressure before taking the drug was 120 mmHg and the sample mean blood pressure after taking the drug was 118 mmHg. The sample standard deviation for the blood pressure before taking the drug was 4 mmHg and the sample standard deviation for the blood pressure after taking the drug was 5 mmHg. Test the hypothesis that the average blood pressure after taking the drug is lower than the average blood pressure before taking the drug using a 0.01 level of significance.IQ tests are approximately normally distributed with a mean of 100 for adults. A tech company CEO wants to conduct a hypothesis test to see if the average IQ of employees at high-tech firms in California is higher than average. What is Type I error in the context of this problem?According to a news program, Americans take an average of 4.9 days off per year because of illness. The manager of a large chain of grocery stores wants to know if the employees at the grocery store, on average, take fewer days off than the national average. The manager selects a random sample of 80 employees in the company and found the sample mean number of days off for the 80 employees was 4.75 days with a standard deviation of 0.9 days. When the manager performed a significance test, the P-value was 0.07. What is the meaning of this P-value in context?
- It currently takes users a mean of 2626 minutes to install the most popular computer program made by RodeTech, a software design company. After changes have been made to the program, the company executives want to know if the new mean is now different from 2626 minutes so that they can change their advertising accordingly. A simple random sample of 5151 new customers are asked to time how long it takes for them to install the software. The sample mean is 24.924.9 minutes with a standard deviation of 2.72.7 minutes. Perform a hypothesis test at the 0.0250.025 level of significance to see if the mean installation time has changed. Step 1 of 3 : State the null and alternative hypotheses for the test. Fill in the blank below. H0Ha: μ=26: μ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯26Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 42 randomly selected people who train in groups and finds that they run a mean of 47.1 miles per week. Assume that the population standard deviation for group runners is known to be 4.4 miles per week. She also interviews a random sample of 47 people who train on their own and finds that they run a mean of 48.5 miles per week. Assume that the population standard deviation for people who run by themselves is 1.8 miles per week. Test the claim at the 0.01 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.A consumer group plans a comparative study of the mean life of four different brands of batteries. Ten batteries of each brand will be randomly selected and the time until the energy level falls below a pre-specified level is measured.
- The University of Montana admission standards require students to have an ACT score of at least 22.We know that Montana ACT scores are normally distributed with a mean of 20.1 and standarddeviation of 4. If we ask a random sample of 100 students who took the ACT, how many would be expected toqualify for admission to UM?According to a study of TV viewing habits, the average number of hours an American over the age of 2 watches TV per week is 44. The population standard deviation is 16 hours. If a sample of 64 Americans over the age of 2 are randomly selected, what is the standard error of the mean?A research article reported that for a random sample of 850 meal purchases made at fast food chain A, the mean number of calories was 1,004, and the standard deviation was 489. For a random sample of 2,108 meal purchases made at fast food chain B, the mean number of calories was 905, and the standard deviation was 622. Based on these samples, is there convincing evidence that the mean number of calories in fast food chain B meal purchases is less than the mean number of calories in fast food chain A meal purchases? (Test the relevant hypotheses using a 0.05 level of significance. Use ?1 for fast food chain B and ?2 for fast food chain A.) State the appropriate null and alternative hypotheses. Find the test statistic and P-value. (Use SALT. Round your test statistic to one decimal place and your P-value to three decimal places.) t= P-value= State the conclusion in the problem context. We fail to reject H0. There is convincing evidence that the mean number of calories in fast food…
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