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A researcher believes that among the residents of a remote community, 30% have type O blood, 50% have type A blood, 10% have type B blood and 10% have type AB blood. She takes a random sample of 80 residents and finds that 20 had type O blood, 40 had type A blood, 12 had type B blood and 8 had type AB blood. Do the data follow the hypothesized distribution of blood type for this community? Test at a = .05. Round your answers to three decimal places, if necessary. Null hypothesis: Ho: Po = Ho: Po Ho: po 0.3, PA = 20 80 1 20 Alternative hypothesis: Ha: Po Туре О 20 PA , PA = Ho: Po = PA = PB = PAB Type O 24 20 0.5, PB 40 80 1 40 PA #PB = PAB = › PB = ,PB Type A = Complete the table of observed counts: 40 Type A Ha: Po Ha: Po At least one of the proportions is different. 0.1, PAB 12 1 4 11 4 40 12 80 80 80 0.3, PA ‡ 0.5, PB ‡ 0.1, PAB ‡ 0.1 80 1 12 › PA # ,PB # PAB # Type B 12 = 0.1 , PAB PAB Type B 8 Complete the table of expected counts under the null hypothesis: 8 80 1 8 8 80 Type AB Type AB 8 Part 2 of 5

A researcher believes that among the residents of a remote community, 30% have type O blood, 50% have type A blood, 10% have type B blood and 10% have type AB blood. She takes a random sample of 80 residents and finds that 20 had type O blood, 40 had type A blood, 12 had type B blood and 8 had type AB blood. Do the data follow the hypothesized distribution of blood type for this community? Test at a = .05. Round your answers to three decimal places, if necessary. Null hypothesis: Ho: Po = Ho: Po Ho: po 0.3, PA = 20 80 1 20 Alternative hypothesis: Ha: Po Туре О 20 PA , PA = Ho: Po = PA = PB = PAB Type O 24 20 0.5, PB 40 80 1 40 PA #PB = PAB = › PB = ,PB Type A = Complete the table of observed counts: 40 Type A Ha: Po Ha: Po At least one of the proportions is different. 0.1, PAB 12 1 4 11 4 40 12 80 80 80 0.3, PA ‡ 0.5, PB ‡ 0.1, PAB ‡ 0.1 80 1 12 › PA # ,PB # PAB # Type B 12 = 0.1 , PAB PAB Type B 8 Complete the table of expected counts under the null hypothesis: 8 80 1 8 8 80 Type AB Type AB 8 Part 2 of 5

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A researcher believes that among the residents of a remote community, 30% have type O blood, 50% have type A blood, 10% have type B blood and 10% have type AB blood. She takes a random sample of 80 residents and finds that 20 had type O blood, 40 had type A blood, 12 had type B blood and 8 had type AB blood. Do the data follow the hypothesized distribution of blood type for this community? Test at a = .05. Round your answers to three decimal places, if necessary. Null hypothesis: Ho: Po Ho: Po Ho: po = Type O = 20 = 0.3, PA Type 0 20 24 80 1 20 Alternative hypothesis: Ha: Po , PA = = , PA = 1 Ho: Po = PA = PB = PAB = 4 0.5, PB 40 80 1 40 PA # PA PB ‡ PAB = = Complete the table of observed counts: Type A 40 ,PB = PB = 40 Ha: Po Ha: Po At least one of the proportions is different. Type A 0.1, PAB 12 80 1 12 20 12 8 80 80 -, PB # PAB # 80 80 0.3, pa ‡ 0.5, pß ‡ 0.1, PAB ‡ 0.1 1 4 Type B 12 0.1 PAB = Type B PAB = Complete the table of expected counts under the null hypothesis: 8 8 80 1 8 Type AB Type AB 8 Part 2 of 5
Transcribed Image Text:A researcher believes that among the residents of a remote community, 30% have type O blood, 50% have type A blood, 10% have type B blood and 10% have type AB blood. She takes a random sample of 80 residents and finds that 20 had type O blood, 40 had type A blood, 12 had type B blood and 8 had type AB blood. Do the data follow the hypothesized distribution of blood type for this community? Test at a = .05. Round your answers to three decimal places, if necessary. Null hypothesis: Ho: Po Ho: Po Ho: po = Type O = 20 = 0.3, PA Type 0 20 24 80 1 20 Alternative hypothesis: Ha: Po , PA = = , PA = 1 Ho: Po = PA = PB = PAB = 4 0.5, PB 40 80 1 40 PA # PA PB ‡ PAB = = Complete the table of observed counts: Type A 40 ,PB = PB = 40 Ha: Po Ha: Po At least one of the proportions is different. Type A 0.1, PAB 12 80 1 12 20 12 8 80 80 -, PB # PAB # 80 80 0.3, pa ‡ 0.5, pß ‡ 0.1, PAB ‡ 0.1 1 4 Type B 12 0.1 PAB = Type B PAB = Complete the table of expected counts under the null hypothesis: 8 8 80 1 8 Type AB Type AB 8 Part 2 of 5
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