Explain the reason for the change in X-ray diffraction (XRD) in different types of materials
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- Question 1: X-ray Diffraction x-ray diffraction is a method used to identify different types of materials. While this is usually quite a complex process, however for a simple cubic structure, as seen below, we can find the distance between neighboring atoms. The below image shows the diffraction of x-rays passing through a cubic structure and illustrates a change in distance of 2d sine Light rays in phase ● a /I\ 100 20. b d sin 8 2d sin 0 Atoms in crystal If the wavelength of the x-ray is equal to an integer multiple of this change in distance, we will get constructive interference: mλ = 2d sine X-rays of wavelength 0.103 nm reflects off a crystal and a second-order maximum is recorded at a Bragg angle of 25.5°. (a) What is the spacing between the scattering planes in this crystal? (b) At what angle will the third-order maximum occur?X rays of wavelength 0.0820 nm are scattered from the atoms of a crystal. The second-order maximum in the Bragg reflection occurs when the angle is 20.5°. (Figure 1) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of X-ray diffraction. Part A What is the spacing between adjacent atomic planes in the crystal? Express your answer in nanometers. ΓΙ ΑΣΦ d = Submit Previous Answers Request Answer ? nmcan you solve step by step
- X-rays of wavelength equal to 0.134 nm give a first order diffraction from the surface of a crystal when the value of 0(theta) is 10.5°. Calculate the distance between the planes in the crystal parallel to the surface examined. Solve correctly please full explanation neededA ray of light is incident on an air/water interface. The ray makes an angle of θ1 = 29 degrees with respect to the normal of the surface. The index of the air is n1 = 1 while water is n2 = 1.33. Write an expression for the reflection angle ψ, with respect to the surface.The inner surface of a fluorescent light bulb is coated with a wavelength shifting material. Without this coating, Question 3 options: The light would be too dim for human eyes. The light would be too bright for human eyes. The light would not escape the bulb. The light would not be visible to human eyes.