Experiment: Preparation of Benzoic Acid Volume of Benzonitrile: 2.0 mL Volume of NaOH (50%): 50 mL Density of Benzonitrile: 1.0 g/mL Mass of Benzoic acid recover: 1.955 gram Melting point of Benzoic acid measured: 118 C
Experiment: Preparation of Benzoic Acid Volume of Benzonitrile: 2.0 mL Volume of NaOH (50%): 50 mL Density of Benzonitrile: 1.0 g/mL Mass of Benzoic acid recover: 1.955 gram Melting point of Benzoic acid measured: 118 C
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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with given data please help me find the percent yield of benzoic acid
Transcribed Image Text:### Experiment: Preparation of Benzoic Acid
**Volume of Benzonitrile:** 2.0 mL
**Volume of NaOH (50%):** 50 mL
**Density of Benzonitrile:** 1.0 g/mL
**Mass of Benzoic Acid Recovered:** 1.955 grams
**Melting Point of Benzoic Acid Measured:** 118°C
---
This data pertains to an experiment focused on the preparation of benzoic acid. The substances used, their volumes, and relevant physical properties are listed to give detailed quantitative backing to the experimental process. Understanding these measurements is crucial for replicating the experiment accurately in an educational or laboratory setting.
![**Calculating Percent Yield of Benzoic Acid**
**Problem Statement:**
Determine the percent yield of benzoic acid. Include the compound name or abbreviation. The detailed working need not be shown in the conclusion.
**Reaction Considered:**
\[ \text{A} \rightarrow \text{B} \]
1. **Conversion Calculation:**
\[
5.00\text{ g A} \times \frac{1 \text{ mol A}}{136 \text{ g A}} \times \frac{1 \text{ mol B}}{1 \text{ mol A}} \times \frac{181 \text{ g B}}{1 \text{ mol B}} = 6.65 \text{ g B}
\]
2. **Molar Mass Relationship:**
\[
136 \text{ g A} \rightarrow 1 \text{ mol A} \rightarrow 1 \text{ mol B}
\]
3. **Expressed as:**
\[
5.00 \text{ g A} \times \left( \frac{1 \text{ mol A}}{136 \text{ g A}} \right) \times \left( \frac{1 \text{ mol A}}{1 \text{ mol B}} \right) \times \left( \frac{181 \text{ g B}}{1 \text{ mol B}} \right) = 6.65 \text{ g B}
\]
This verbose representation should accurately depict how to compute the percent yield from a given substance A to product B, considering their respective molar masses and the stoichiometry of the reaction.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc02bfde4-a78d-4551-93f6-03d589a5c8dc%2F80626f09-6df7-49eb-b414-d168479459a4%2Fnqm7hgf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Calculating Percent Yield of Benzoic Acid**
**Problem Statement:**
Determine the percent yield of benzoic acid. Include the compound name or abbreviation. The detailed working need not be shown in the conclusion.
**Reaction Considered:**
\[ \text{A} \rightarrow \text{B} \]
1. **Conversion Calculation:**
\[
5.00\text{ g A} \times \frac{1 \text{ mol A}}{136 \text{ g A}} \times \frac{1 \text{ mol B}}{1 \text{ mol A}} \times \frac{181 \text{ g B}}{1 \text{ mol B}} = 6.65 \text{ g B}
\]
2. **Molar Mass Relationship:**
\[
136 \text{ g A} \rightarrow 1 \text{ mol A} \rightarrow 1 \text{ mol B}
\]
3. **Expressed as:**
\[
5.00 \text{ g A} \times \left( \frac{1 \text{ mol A}}{136 \text{ g A}} \right) \times \left( \frac{1 \text{ mol A}}{1 \text{ mol B}} \right) \times \left( \frac{181 \text{ g B}}{1 \text{ mol B}} \right) = 6.65 \text{ g B}
\]
This verbose representation should accurately depict how to compute the percent yield from a given substance A to product B, considering their respective molar masses and the stoichiometry of the reaction.
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