1.00 g of benzoic acid corresponds to how many mmols of this compound?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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### Question:
1.00 g of benzoic acid corresponds to how many mmol of this compound?

### Explanation:
To find the number of millimoles (mmol) of benzoic acid in 1.00 g, you need to use the formula:

\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]

Given:
- Mass of benzoic acid = 1.00 g
- Molar mass of benzoic acid = 122.12 g/mol (The molar mass can be found from a chemical database or periodic table)

Steps:
1. First, calculate the moles of benzoic acid:
   
   \[ \text{Number of moles} = \frac{1.00 \text{ g}}{122.12 \text{ g/mol}} = 0.00819 \text{ moles} \]

2. Convert moles to millimoles (mmol), recognizing that 1 mole = 1000 mmol:

   \[ 0.00819 \text{ moles} \times 1000 = 8.19 \text{ mmol} \]

Therefore, 1.00 g of benzoic acid corresponds to 8.19 mmol of the compound.

This detailed conversion provides a clear understanding of how to determine the amount of a substance in millimoles, which is a common requirement in chemistry calculations.
Transcribed Image Text:### Question: 1.00 g of benzoic acid corresponds to how many mmol of this compound? ### Explanation: To find the number of millimoles (mmol) of benzoic acid in 1.00 g, you need to use the formula: \[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \] Given: - Mass of benzoic acid = 1.00 g - Molar mass of benzoic acid = 122.12 g/mol (The molar mass can be found from a chemical database or periodic table) Steps: 1. First, calculate the moles of benzoic acid: \[ \text{Number of moles} = \frac{1.00 \text{ g}}{122.12 \text{ g/mol}} = 0.00819 \text{ moles} \] 2. Convert moles to millimoles (mmol), recognizing that 1 mole = 1000 mmol: \[ 0.00819 \text{ moles} \times 1000 = 8.19 \text{ mmol} \] Therefore, 1.00 g of benzoic acid corresponds to 8.19 mmol of the compound. This detailed conversion provides a clear understanding of how to determine the amount of a substance in millimoles, which is a common requirement in chemistry calculations.
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