Experiment 1 Data Table 2: Experimental Results HCI available 0.1823 for neutralization (g): Moles of 0.005 NaOH required to reach stoichiometric point (mol): HCI neutralized by antacid (g): HCI neutralized per gram of aid (g): 0.109 0.218

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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If you perform this experiment with a titrant of 0.5M NaOH , would you expect your results in Data Table 2 to change or stay the same? Explain the answer.
Experiment 1
Data Table 2: Experimental Results
HCI available
0.1823
for
neutralization
(g):
Moles of
0.005
NaOH
required to
reach
stoichiometric
point (mol):
HCI
0.109
neutralized by
antacid (g):
HCI
neutralized
per gram of
aid (g):
0.218
Transcribed Image Text:Experiment 1 Data Table 2: Experimental Results HCI available 0.1823 for neutralization (g): Moles of 0.005 NaOH required to reach stoichiometric point (mol): HCI 0.109 neutralized by antacid (g): HCI neutralized per gram of aid (g): 0.218
Experiment 1
Data Table 1: Antacid Neutralization Data
Mass of
0.5
Crushed
Antacid (g)
Concentration 1.0
of HCI (M)
Volume HCI
5.0
(mL)
Concentration 1.0
of NaOH (M)
Initial NaOH
6
Volume (mL)
Final NaOH
4
Volume (mL)
Total Volume
-2
of NaOH
(mL)
Transcribed Image Text:Experiment 1 Data Table 1: Antacid Neutralization Data Mass of 0.5 Crushed Antacid (g) Concentration 1.0 of HCI (M) Volume HCI 5.0 (mL) Concentration 1.0 of NaOH (M) Initial NaOH 6 Volume (mL) Final NaOH 4 Volume (mL) Total Volume -2 of NaOH (mL)
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