Exp #14: Titration 1) Standardization of NaOH with HCL. Molarity of HCI_I. DI 3 L. Volume HCI Used Volume HCI Used 25.00 Moles HCI Used M ml mol Initial Vol of NaOH_0.00 ml. Final Vol NaOH 21.5 ml Volume NaOH Used Molarity of NaOH Standard_{. 178 M Show Calculations for Molarity of NAOH: 2) Determination of Acetic Acid Concentration mly or Volume Vinegar Used 20.00 L 0.02000 L Molarity of NaOH_ 0.50 M Initial Vol of NaOH_ 0.60 mL Final Vol NaOH 35.45 mL Volume NaOH Used Moles NaOH Used mol Moles of CH,COOH mol Molarity of Vinegar M Chow Calculations for moles of NaOH and molarity of vinegar:

Exp #14: Titration 1) Standardization of NaOH with HCL. Molarity of HCI_I. DI 3 L. Volume HCI Used Volume HCI Used 25.00 Moles HCI Used M ml mol Initial Vol of NaOH_0.00 ml. Final Vol NaOH 21.5 ml Volume NaOH Used Molarity of NaOH Standard_{. 178 M Show Calculations for Molarity of NAOH: 2) Determination of Acetic Acid Concentration mly or Volume Vinegar Used 20.00 L 0.02000 L Molarity of NaOH_ 0.50 M Initial Vol of NaOH_ 0.60 mL Final Vol NaOH 35.45 mL Volume NaOH Used Moles NaOH Used mol Moles of CH,COOH mol Molarity of Vinegar M Chow Calculations for moles of NaOH and molarity of vinegar:

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

Exp #14: Titration
1) Standardization of NaOH with HCl.
Molarity of HCl_ 1.013
Volume HCI Used
Volume HCI Used 25.00
ml
M
Moles HCI Used
mol
ml
Final Vol NaOH 21.5
mL
Initial Vol of NaOH_0.00
Volume NaOH Used
Molarity of NaOH Standard_{, 78 m
Show Calculations for Molarity of NaOH:
2) Determination of Acetic Acid Concentration
mly or o.02000 L
Molarity of NaOH_0.50 M
Volume Vinegar Used 20.00 L
Initial Vol of NaOH 0.60
mL
Final Vol NaOH 35.45
mL
Volume NaOH Used
L
Moles NaOH Used
mol
Moles of CH,COOH_
mol
Molarity of Vinegar
M
Show Calculations for moles of NaOH and molarity of vinegar:

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Determine the resulting pH when 0.003 mol of solid NaOH is added to a 100.0 mL buffer containing 0.13 M HClO and 0.37 M NaClO. The value of Ka for HClO is 2.9 × 10⁻⁸ Please solve for the pH
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A 50.00 mL of 0.0275 M HCl solution was titrated with 0.1500 M NaOH. Calculate the pH of the analyte solution in the specified volumes of the titrant added. At 5 mL of the titrant. -1.26 -1.56 -1.86 -2.06 At 14 mL of the titrant. -10.23 -11.78 -12.23 -13.78 At 20 mL of the titrant. -10.23 -11.78 -12.23 -13.78
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