Determine the pH at the point in the titration of 40.0 mL of 0.200 M H,NNH, with 0.100 M HNO, after 10.0 mL of the strong acid has been added. The value of Kb for H,NNH, is 3.0 x 10°. 1 2 3 4 NEXT> Use the table below to determine the moles of reactant and product after the reaction of the acid and base. H,NNH,(aq) + H*(aq) H,NNH, (aq) Before (mol) Change |(mol) After (mol) 100 00
Determine the pH at the point in the titration of 40.0 mL of 0.200 M H,NNH, with 0.100 M HNO, after 10.0 mL of the strong acid has been added. The value of Kb for H,NNH, is 3.0 x 10°. 1 2 3 4 NEXT> Use the table below to determine the moles of reactant and product after the reaction of the acid and base. H,NNH,(aq) + H*(aq) H,NNH, (aq) Before (mol) Change |(mol) After (mol) 100 00
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter14: Equilibria In Acid-base Solutions
Section: Chapter Questions
Problem 33QAP: A buffer is prepared in which the ratio [ H2PO4 ]/[ HPO42 ]is 3.0. (a) What is the pH of this...
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![Question 9 of 9
Šubmit
Determine the pH at the point in the titration of 40.0 mL of
0.200 M H,NNH, with 0.100 M HNO, after 10.0 mL of the
strong acid has been added. The value of Kb for H,NNH,
is 3.0 x 10°.
1
2
NEXT>
Use the table below to determine the moles of reactant and product
after the reaction of the acid and base.
H,NNH,(aq) +
H*(aq)
H,NNH,"(aq)
Before
(mol)
Change
(mol)
After (mol)
CRESET
0.200
0.100
1.00 x 103
-1.00 x 103
2.00 x 103
-2.00 x 10*
6.00 x 103
-6.00 x 103
7.00 x 103
-7.00 x 103
8.00 x 103
-8.00 x 103](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc93c4c2c-87bf-4a2e-b2f9-fa896ab5e7e6%2Fb4860731-5077-46ee-afc3-a65cbd595e1b%2Fwujghi_processed.png&w=3840&q=75)
Transcribed Image Text:Question 9 of 9
Šubmit
Determine the pH at the point in the titration of 40.0 mL of
0.200 M H,NNH, with 0.100 M HNO, after 10.0 mL of the
strong acid has been added. The value of Kb for H,NNH,
is 3.0 x 10°.
1
2
NEXT>
Use the table below to determine the moles of reactant and product
after the reaction of the acid and base.
H,NNH,(aq) +
H*(aq)
H,NNH,"(aq)
Before
(mol)
Change
(mol)
After (mol)
CRESET
0.200
0.100
1.00 x 103
-1.00 x 103
2.00 x 103
-2.00 x 10*
6.00 x 103
-6.00 x 103
7.00 x 103
-7.00 x 103
8.00 x 103
-8.00 x 103
![Determine the pH at the point in the titration of 40.0 mL of
0.200 M H,NNH, with 0.100 M HNO, after 10.0 mL of the
strong acid has been added. The value of Kb for H,NNH,
is 3.0 x 10°.
( PREV
2
3.
4
NEXT>
Based on the result of the acid-base reaction, set up the ICE table in
order to determine the unknown.
H,NNH,(aq) +
H,O(1) = OH(aq) +H¸NNH,*(aq)
|Initial
(M)
Change
(M)
Equilibri
um (M)
ORESET
0.200
0.0200
0.100
0.140
0.175
+x
0.200 + x
0.200 - х
0.0200 + x
0.0200 - x
0.100 + x
0.100 - x
0.140 + x
-x
0.140 - x
0.175 + x
0.175 - x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc93c4c2c-87bf-4a2e-b2f9-fa896ab5e7e6%2Fb4860731-5077-46ee-afc3-a65cbd595e1b%2Fsjng3uu_processed.png&w=3840&q=75)
Transcribed Image Text:Determine the pH at the point in the titration of 40.0 mL of
0.200 M H,NNH, with 0.100 M HNO, after 10.0 mL of the
strong acid has been added. The value of Kb for H,NNH,
is 3.0 x 10°.
( PREV
2
3.
4
NEXT>
Based on the result of the acid-base reaction, set up the ICE table in
order to determine the unknown.
H,NNH,(aq) +
H,O(1) = OH(aq) +H¸NNH,*(aq)
|Initial
(M)
Change
(M)
Equilibri
um (M)
ORESET
0.200
0.0200
0.100
0.140
0.175
+x
0.200 + x
0.200 - х
0.0200 + x
0.0200 - x
0.100 + x
0.100 - x
0.140 + x
-x
0.140 - x
0.175 + x
0.175 - x
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