EXERCISE 1: Kinetic study of urea decomposition In aqueous solution, urea ((NH2)2CO) is likely to decompose into ammonium carbonate according to the reaction: .(H,N), CO+..H,O→..H; +...CO" The reaction rate constant at 350K is 4×10-5 s-1, 5. Compute the time ti required at 350K to decompose 80% of urea. The answer If we decompose 80% of urea, then 0.2 CO of urea is left. Thus In0. 2 = In0.2 In0.2 -kt, i.e. t1 . NA: t1 4x10-5=40236 s= 11,18h k Can you Explain Why?

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EXERCISE 1: Kinetic study of urea decomposition
In aqueous solution, urea ((NH2)2CO) is likely to decompose into ammonium carbonate
according to the reaction :
.. ..NH; +
(H,N),CO+....H,O→
„Co
2
The reaction rate constant at 350K is 4x10-5 s-1,
5. Compute the time ti required at 350K to decompose 80% of urea.
The answer If we decompose 80% of urea, then 0.2 C0 of urea is left. Thus In0. 2 =
In0.2
-kt, i.e. t1
NA: t1
k
In0.2
==40236 s= 11,18h
-
= -
4x10-5
Can you Explain Why?
Transcribed Image Text:EXERCISE 1: Kinetic study of urea decomposition In aqueous solution, urea ((NH2)2CO) is likely to decompose into ammonium carbonate according to the reaction : .. ..NH; + (H,N),CO+....H,O→ „Co 2 The reaction rate constant at 350K is 4x10-5 s-1, 5. Compute the time ti required at 350K to decompose 80% of urea. The answer If we decompose 80% of urea, then 0.2 C0 of urea is left. Thus In0. 2 = In0.2 -kt, i.e. t1 NA: t1 k In0.2 ==40236 s= 11,18h - = - 4x10-5 Can you Explain Why?
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