The activation energy for the gas phase decomposition of t-butyl alcohol is 274 kJ. (CH3)3COH(CH3)2C=CH2 + H2O The rate constant at 803.0K is 0.000710/s. The rate constant will be  _______/s at 852.0K.

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The activation energy for the gas phase decomposition of t-butyl alcohol is 274 kJ.

(CH3)3COH(CH3)2C=CH2 + H2O
The rate constant at 803.0K is 0.000710/s. The rate constant will be  _______/s at 852.0K. 

Expert Solution
Step 1

Arrhenius equation:
If we know the value of the rate constant at two different temperatures, we can calculate the activation energy by using the Arrhenius equation. The Arrhenius equation is given by:

Chemistry homework question answer, step 1, image 1

where k= rate constant at the T2 temperature

k1 = rate constant at T1 = 0.000710 s-1

Ea = activation energy = 274 kJ/mol

R = gas constant = 8.314 J/K.mol

T1 = 803.0 K

T2 = 852.0 K

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