The activation energy for the gas phase decomposition of t-butyl alcohol is 274 kJ. (CH3)3COH(CH3)2C=CH2 + H2O The rate constant at 803.0K is 0.000710/s. The rate constant will be _______/s at 852.0K.
The activation energy for the gas phase decomposition of t-butyl alcohol is 274 kJ. (CH3)3COH(CH3)2C=CH2 + H2O The rate constant at 803.0K is 0.000710/s. The rate constant will be _______/s at 852.0K.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The activation energy for the gas phase decomposition of t-butyl alcohol is 274 kJ.
(CH3)3COH(CH3)2C=CH2 + H2O
The rate constant at 803.0K is 0.000710/s. The rate constant will be _______/s at 852.0K.
Expert Solution

Step 1
Arrhenius equation:
If we know the value of the rate constant at two different temperatures, we can calculate the activation energy by using the Arrhenius equation. The Arrhenius equation is given by:
where k2 = rate constant at the T2 temperature
k1 = rate constant at T1 = 0.000710 s-1
Ea = activation energy = 274 kJ/mol
R = gas constant = 8.314 J/K.mol
T1 = 803.0 K
T2 = 852.0 K
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