The activation energy for the gas phase išófme CH2)3 CH3CH=CH, The rate constant at 769.0 K is 0.000478 /s. The rate constant will be /s at 817.0 Submit Answer Retry Entire Group 9 more group attempts remaining

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Gas Phase Isomerization of Cyclopropane**

*Introduction:*

The activation energy for the gas phase isomerization of cyclopropane is 272 kJ.

*Isomerization Reaction:*

\[
\text{(CH}_2\text{)}_3 \rightarrow \text{CH}_3\text{CH=CH}_2
\]

*Rate Constant Information:*

- The rate constant at 769.0 K is 0.000478 /s.
- Calculate the rate constant at 817.0 K.

*Instructions for Students:*

- Use references if needed to determine important values for the calculation.
- Complete the blank in the statement: "The rate constant will be ______ /s at 817.0 K."

*Submission Options:*

- Click "Submit Answer" after completing your calculation.
- Click "Retry Entire Group" if you need another attempt.
- Note: 9 more group attempts remaining.
Transcribed Image Text:**Gas Phase Isomerization of Cyclopropane** *Introduction:* The activation energy for the gas phase isomerization of cyclopropane is 272 kJ. *Isomerization Reaction:* \[ \text{(CH}_2\text{)}_3 \rightarrow \text{CH}_3\text{CH=CH}_2 \] *Rate Constant Information:* - The rate constant at 769.0 K is 0.000478 /s. - Calculate the rate constant at 817.0 K. *Instructions for Students:* - Use references if needed to determine important values for the calculation. - Complete the blank in the statement: "The rate constant will be ______ /s at 817.0 K." *Submission Options:* - Click "Submit Answer" after completing your calculation. - Click "Retry Entire Group" if you need another attempt. - Note: 9 more group attempts remaining.
Expert Solution
Step 1

 

Ea=272 kJ=272000 JT1=769 KT2=817 Kk1=0.000478k2=?

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