Example Problem: Estimate Ke At 400°C For N₂+ 3H₂2 → 2NH3: • AS°=-198.3 J/K. • AH°= -92.38 kJ. • AG˚rxn = -33.32 kJ. AG° • Keq at 298 K = 6.9 x 105. eq-
Example Problem: Estimate Ke At 400°C For N₂+ 3H₂2 → 2NH3: • AS°=-198.3 J/K. • AH°= -92.38 kJ. • AG˚rxn = -33.32 kJ. AG° • Keq at 298 K = 6.9 x 105. eq-
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Example Problem: Estimate Ke At 400°C For N₂+ 3H₂2 → 2NH3:
• AS°=-198.3 J/K.
• AH°= -92.38 kJ.
• AG˚rxn = -33.32 kJ.
AG°
• Keq at 298 K = 6.9 x 105.
eq-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa5a83280-4efa-44b2-8686-8f6316a9b382%2F0441d8e4-cac4-47c6-a0c7-e03301328dc8%2Fstyxseo_processed.png&w=3840&q=75)
Transcribed Image Text:Example Problem: Estimate Ke At 400°C For N₂+ 3H₂2 → 2NH3:
• AS°=-198.3 J/K.
• AH°= -92.38 kJ.
• AG˚rxn = -33.32 kJ.
AG°
• Keq at 298 K = 6.9 x 105.
eq-
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