What is Sº for A in the reaction 3 A → 2 Bif AS°(rxn) =-282.7 J/mol · K? [S° (B) = (240.0 J/mol ·K)]

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question:**  
What is \( S^\circ \) for A in the reaction \( 3 \, \text{A} \rightarrow 2 \, \text{B} \) if \(\Delta S^\circ (\text{rxn}) = -282.7 \, \text{J/mol} \cdot \text{K}\)? \([S^\circ (\text{B}) = 240.0 \, \text{J/mol} \cdot \text{K}]\)  

**Explanation:**  
This chemistry problem involves calculating the standard molar entropy (\( S^\circ \)) for a reactant A in a given chemical reaction, using the provided reaction entropy change \(\Delta S^\circ\) and the standard molar entropy for product B.

**Equation:**  
To find \( S^\circ \) for A, the entropy change of the reaction (\(\Delta S^\circ \)) is related to the standard molar entropies of the reactants and products using the equation:

\[
\Delta S^\circ = \sum \text{S}^\circ (\text{products}) - \sum \text{S}^\circ (\text{reactants})
\]

By plugging in the known values and solving for the unknown \( S^\circ \) of A, you can address the question.
Transcribed Image Text:**Question:** What is \( S^\circ \) for A in the reaction \( 3 \, \text{A} \rightarrow 2 \, \text{B} \) if \(\Delta S^\circ (\text{rxn}) = -282.7 \, \text{J/mol} \cdot \text{K}\)? \([S^\circ (\text{B}) = 240.0 \, \text{J/mol} \cdot \text{K}]\) **Explanation:** This chemistry problem involves calculating the standard molar entropy (\( S^\circ \)) for a reactant A in a given chemical reaction, using the provided reaction entropy change \(\Delta S^\circ\) and the standard molar entropy for product B. **Equation:** To find \( S^\circ \) for A, the entropy change of the reaction (\(\Delta S^\circ \)) is related to the standard molar entropies of the reactants and products using the equation: \[ \Delta S^\circ = \sum \text{S}^\circ (\text{products}) - \sum \text{S}^\circ (\text{reactants}) \] By plugging in the known values and solving for the unknown \( S^\circ \) of A, you can address the question.
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