Example : Estimating the sample size The lengths of metal rods produced by an industrial process are normally distributed with standard deviation 1.8 mm. Suppose that a production manager requires a 99% confidence interval extending no further than 0.5mm on each side of the sample mean. How large a sample is needed to achieve such an interval? Objective: n for 99% confidence interval Za/20x Clo,99(Hx): W = 2 vn < 2(0.5) Available information: Available information: Population : X= length of a metal rods (mm) X~N(µx, o Sample : SRS with size: n =? = 1.82) %3D

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Example : Estimating the sample size
The lengths of metal rods produced by an industrial process are normally distributed with
standard deviation 1.8 mm. Suppose that a production manager requires a 99% confidence
interval extending no further than 0.5mm on each side of the sample mean. How large a
sample is needed to achieve such an interval?
Za/20x
Objective: n for 99% confidence interval
Clo,99(Hx): W = 2
yn
< 2(0.5)
Available information:
Available information:
o Population :
X= length of a metal rods (mm)
X~N(Hx, o = 1.82)
Sample :
SRS with size: n =?
%3D
38
Transcribed Image Text:E | D Page view A Read aloud |V Draw Y Highlight O Erase G 37 Example : Estimating the sample size The lengths of metal rods produced by an industrial process are normally distributed with standard deviation 1.8 mm. Suppose that a production manager requires a 99% confidence interval extending no further than 0.5mm on each side of the sample mean. How large a sample is needed to achieve such an interval? Za/20x Objective: n for 99% confidence interval Clo,99(Hx): W = 2 yn < 2(0.5) Available information: Available information: o Population : X= length of a metal rods (mm) X~N(Hx, o = 1.82) Sample : SRS with size: n =? %3D 38
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