es A sample of 12 fossil skeletons of an extinct species of bird has been collected. The mean length of the skulls in this sample is 5.29 cm and the standard deviation of the sample is 0.21 cm. Assuming that such measurements are normally distributed, find a 90% confidence interval for the population mean length of the skulls of this species of bird. You may want to use one of these: qt (p-0.10, df-11, lower. tail-FALSE)=1.36343 qt(p-0.05, df-11, lower.tail-FALSE) =1.795885 qnorm(0.10, mean-0, sd-1, lower.tail-FALSE)=1.281552 qnorm(0.05, mean-0, sd-1, lower.tail=FALSE)=1.644854 O (4.945, 5.635) O (4.913, 5.667) O (5.021, 5.559) O (5.181, 5.399)
es A sample of 12 fossil skeletons of an extinct species of bird has been collected. The mean length of the skulls in this sample is 5.29 cm and the standard deviation of the sample is 0.21 cm. Assuming that such measurements are normally distributed, find a 90% confidence interval for the population mean length of the skulls of this species of bird. You may want to use one of these: qt (p-0.10, df-11, lower. tail-FALSE)=1.36343 qt(p-0.05, df-11, lower.tail-FALSE) =1.795885 qnorm(0.10, mean-0, sd-1, lower.tail-FALSE)=1.281552 qnorm(0.05, mean-0, sd-1, lower.tail=FALSE)=1.644854 O (4.945, 5.635) O (4.913, 5.667) O (5.021, 5.559) O (5.181, 5.399)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:es
A sample of 12 fossil skeletons of an extinct species of bird has been collected. The mean
length of the skulls in this sample is 5.29 cm and the standard deviation of the sample is
0.21 cm. Assuming that such measurements are normally distributed, find a 90% confidence
interval for the population mean length of the skulls of this species of bird.
You may want to use one of these:
qt (p-0.10, df-11, lower. tail-FALSE)=1.36343
qt(p-0.05, df-11, lower.tail-FALSE) =1.795885
qnorm(0.10, mean-0, sd-1, lower.tail-FALSE)=1.281552
qnorm(0.05, mean-0, sd-1, lower.tail=FALSE)=1.644854
O (4.945, 5.635)
O (4.913, 5.667)
O (5.021, 5.559)
O (5.181, 5.399)
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