Body Mass Index: In a survey of adults with diabetes, the average body mass index (BMI) in a sample of 1935 women was 32.50 with a standard deviation of0.2. The average BMI in a sample of 1564 men was 30.80, with a standard deviation of 0.5.Part: 0/ 2Part 1 of 2Construct 99.9% confidence interval for the difference in the mean BMI between women and men with diabetes. Let u, denote the mean BMI for womenwith diabetes. Use tables to find the critical value and round the answers to at least two decimal places.99.9% confidence interval for the difference in the mean BMI between women and men with diabetes isO< H1 - Hz <MicrosNOV22...MacBook Air888DIIDDF5F6F7F8F9F3F4

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Answered: Body Mass Index: In a survey of adults…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Scores on a statistics final in a large class were normally distributed with a mean of 75 and a standard deviation of 8. The instructor wants to give an A to the students whose scores were in the top 08% of the class (Provide your answer with two decimal places). Find the Z-score that is associated with the lowest possible score to get an A. What is the minimum score needed to get an A?
#4data: 0.06, 0.11, 0.16, 0.15, 0.14, 0.08, 0.15. Use the sample data from #4 to construct a 98% confidence interval estimate for the standard deviation of the amount nitrogen-oxide emission for all cars.
A statistics teacher taught a large introductory statistics class, with 500 students having enrolled over many years. The mean score over all those students on the first midterm was u = 88 with standard deviation o = 10. One year, the teacher taught a %3D much smaller class of only 25 students. The teacher wanted to know if teaching a smaller class was more effective and students performed better. We can consider the small class as an SRS of the students who took the large class over the years. The average midterm score was = 78. The hypothesis should be: a. Ho: H = 78 vs. Ha: H = 88. %3D O b. Ho: µ = 88 vs. Ha: µ 78 %3D Ο d. Ho: μ-88 νs. Ha: μ >88. %3D
The mean score on a driving exam for a group of driver’s education students is 76 points, with a standard deviation of 6 points. Apply chebychev’s theorem to the data using K=2. Interpret, At least ___% of the exam score falls between ___and ____
a group of 59 randomly selected students have a mean score of 29.5 with a standard deviation of 5.2 on a placement test. what is the 90% confidence interval for the mean score, u, of all students taking the test?
Energy drinks: A survey of college students reported that in a sample of 402 male college students, the average number of energy drinks consumed per month was 2.41 with a standard deviation of 3.18, and in a sample of 390 female college students, the average was 1.50 with a standard deviation of 4.77. Part: 0/2 Part 1 of 2 Construct a 80% confidence interval for the difference between men and women in the mean number of energy drinks consumed. Let μ, denote the mean number of energy drinks consumed by men. Use tables to find the critical value and round the answers to at least two decimal places. A 80% confidence interval for the difference between men and women in the mean number of energy drinks consumed is 0<44-₂2 <0. X S Part: 1/2 Part 2 of 2 Based on the confidence interval, is it reasonable to believe that the mean number of energy drinks consumed may be the same for both male and female college students? It (Choose one) reasonable to believe that the mean number of energy drinks…
A researcher collected sample data for 10 women ages 18 to 24. The sample had a mean serum cholesterol level (measured in mg/100 mL) of 188.4, with a standard deviation of 5.7. Assuming that serum cholesterol levels for women ages 18 to 24 are normally distributed, find a 99% confidence interval for the mean serum cholesterol level of all women in this age group. Then find the lower limit and upper limit of the 99% confidence interval.
A ecologist wishes to estimate the mean lifespan for a specific species of bird. Assume that bird lifespan is normally distributed and that each bird's lifespan is independent of all others. The researcher analyzes a random sample of n=7 deceased birds to find out how long they lived for. It is found that the mean lifespan in the sample is y= 5 4 years with standard deviation s=13 years. Choose the correct formula for a 95% confidence interval for the true mean lifespan. X± to.975,n O xt to.975,n-1 n-1 O none of these X+ Z0.975 O x+ to.975,n-1' O xt to.975,n-15
75 specimens of the new chip were tested and 67 specimens of the old chip were tested. The average speed, in MHz, for the new chips was 494.9 and the standard deviation was 19.3. The average speed of the old chips was 485.8 and the standard deviation was 16.7. Suppose we wish to test Ho : Hx - Hy = 0 versus H1 : Hx - Hy # 0. Calculate the z-score. (answers are considered correct if they're within 5% of the correct value)
A random sample of 9 observations from a normally distributed population produced a mean x̅ =12.4 and a standard deviation s= 2.8. find a 99% confidence interval for the population mean?

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