The P-value for this hypothesis was found to be:
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- Consider the following hypothesis test: Ho : μ > 45 Ha : μ < 45 A sample of 36 is used. Identify the p-value and state your conclusion for each of the following sample results. Use a = 0.01, a. With 44 and s= 5.2, the p-value is less than 0.005 Can it be concluded that the population mean is less than 45 ? No b. With = 43 and s= = 4.6, the p-value is between 0.01 and 0.025 ✓ Can it be concluded that the population mean is less than 45? Yes c. With = 46 and 8 = 5, the p-value is between 0.01 and 0.025 Can it be concluded that the population mean is less than 45? YesAccording to a 2017 survey by a reputable organization, patients had to wait an average of 24 days to schedule a new appointment with a doctor. A random sample of 40 patients in 2018 was selected and the number of days they had to wait to schedule an appointment was recorded, with the accompanying results. Complete parts a and b. a. Perform a hypothesis test usingα=0.01 to determine if the average number of days appointments are booked in advance has changed since 2017. 1. Determine the null and alternative hypotheses. 2. Determine the appropriate critical value. 3. Select the correct choice below and fill in the answer box within your choice. (Round to three decimal places as needed.) A −tα= B.tα/2= C.tα= 4. Calculate the test statistic 5. P Value 6. State the conclusionFor the following hypothesis test find the p-value. Report the p-value exactly as it is shown in the z-table. Họ: H1 H2 H1: H1 H2 , Z = 2.75, the p-value = %3D Ho: H1 = H2 H1:: µ1 # µ2 , Z= .98, the p-value =
- For each of the following, explain what is wrong and why. a)In simple linear regression, the null hypothesis of the ANOVA F test is H0: β0 = 0. b)In an ANOVA table, the mean squares add. In other words, MST = MSM + MSE. c)The smaller the P-value for the ANOVA F test, the greater the explanatory power of the model. d)The total degrees of freedom in an ANOVA table are equal to the number of observations n.State the Result: A hypothesis test was conducted at the alpha = 0.01 level of significance. The test resulted in a p-value of 0.044. %3D a) Should Ho be rejected?: Reject Ho Fail to Reject Ho b) What is the correct conclusion? There is sufficient evidence to accept the Null Hypothesis O There is sufficient evidence to reject the Null Hypothesis and accept the alternative. OThe evidence has proved the Null Hypothesis to be incorrect. There is not sufficient evidence to reject the Null Hypothesis and accept the alternative.Which of the following statements is true?A) A P-value of 0.011 is weaker evidence against thenull hypothesis than a P-value of 0.033.B) If we reject the null hypothesis at a = 0.05, we’d alsoreject it at a = 0.01.C) We can increase the power of a test by decreasing thesignificance level from 5% to 1%. D) We can decrease the risk of a Type I error by increas-ing the significance level from 1% to 5%. E) The farther the true parameter is from the value wehypothesized, the lower the risk of Type II error.
- For each of the following scenarios, select the test (from the choices below), that is most appropriate for analyzing the data. a) Z-test b) One-sample t-test c) Independent t-test d) Dependent t-test e) 1-Way ANOVA f) Regression/Correlation g) Chi-Square 1. A psychologist wants to know if children with a schizophrenic parent are less well-adjusted than the general population, so she gives 20 children of schizophrenics a measure of psychological adjustment which has a mean of 35 in the general population. 2. A researcher wants to know if 5-yr-old boys and girls differ in their social skills. He recruits 30 brother and sister pairs and administers a social skills inventory with scores that can range from 0 to 80. 3. A sample of 60 children are asked to choose their favorite toy among 3 options (stuffed bear, stuffed dog, stuffed cat). Do children prefer these 3 toys equally?Which is not a step in hypothesis testing? A. Determine or establish alpha B. Determine or establish beta C. Calulate or look up the critical value(s) D. Calculate the test statistic E. All of the above F. None of the aboveWhich of the following is not an interpretation of the null hypothesis: a. The "no effect" value of the population parameter. b. The "supposed value" of the population parameter. c. The hypothesis on which the burden of proof is placed. d. All values of the parameter not specified under the alternative hypothesis. e. All of the above.
- Calculate the p-value for the following conditions and determine whether or not to reject the null hypothesis. a) one-tail (upper) test, z, =2.17, and c=0.10 b) one-tail (lower) test, zn = - 1.49, and a=0.05 c) two-tail test, zn = - 1.71, and o=0.05 d) two-tail test, z, =1.26, and c=0.02 Click here to view the first page of the standard normal table. Click here to view the second page of the standard normal table a) p-value = (Round to four decimal places as needed.) Determine whether or not to reject the null hypothesis. Choose the correct answer below. O A. Reject Ho, since the p-value is less than the significance level o. O B. Do not reject Ho, since the p-value is greater than or equal to the significance level d. O C. Do not reject Ho, since the p-value is less than the significance level o. O D. Reject Ho, since the p-value is greater than or equal to the significance level .Consider the following hypothesis test. Ho : H1 – H2 = 0 H, : 41 – 42 + 0 The following results are from independent samples taken from two populations. Sample 1 Sample 2 n1 = 35 n2 = 40 T1 = 13.6 T2 = 10.1 81 = 5.5 82 = 8.2 a. What is the value of the test statistic (to 2 decimals)? b. What is the degrees of freedom for the t distribution (round the answer to the previous whole number)?Calculate the p-value for the following conditions and determine whether or not to reject the null hypothesis. a) one-tail test, z; = 1.40, and a = 0.02 b) one-tail test, z, = - 2.55, and a = 0.10 c) two-tail test, z, = 2.60, and a = 0.02 d) two-tail test, = - 1.66, and a = 0.05 Click here to view page 1 of the cumulative probabilities for the standard normal distribution. Click here to view page 2 of the cumulative probabilities for the standard normal distribution.