The P-value for this hypothesis was found to be:
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- Calculate the p-value for the following conditions and determine whether or not to reject the null hypothesis. a) one-tail test, z; = 1.40, and a = 0.02 b) one-tail test, z, = - 2.55, and a = 0.10 c) two-tail test, z, = 2.60, and a = 0.02 d) two-tail test, = - 1.66, and a = 0.05 Click here to view page 1 of the cumulative probabilities for the standard normal distribution. Click here to view page 2 of the cumulative probabilities for the standard normal distribution.State the Result: A hypothesis test was conducted at the alpha = 0.01 level of significance. The test resulted in a p-value of 0.044.Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load passengers, and a flight has fuel and baggage that allows for a total passenger load of 5,670 lb. The pilot sees that the plane is full and all passengers are the aircraft. The aircraft can carry 35 5,670 lb men. The aircraft will be overloaded if the mean weight of the passengers is greater than = 162 lb. What is the probability that the aircraft is 35 overloaded? Should the pilot take any action to correct for an overloaded aircraft? Assume that weights of men are normally distributed with a mean of 182.8 lb and a standard deviation of 39.3. The probability is approximately. (Round to four decimal places as needed.) Should the pilot take any action to correct for an overloaded aircraft? O A. Yes. Because the probability is high, the pilot should take action by somehow reducing the weight of the aircraft. O B. No. Because the probability is high, the aircraft is safe to…
- Calculate the p-value for the following conditions and determine whether or not to reject the null hypothesis. Complete parts a through d. a. One-tail (lower) test, zp = -1.19, and x = 0.05. p-value= (Round to four decimal places as needed.)Use the output provided in the formula sheets folder. What is your null hypothesis for the test in question 39? O Ho : B3 = B4 = B5 = 0 Ho : Bo = 0 O Ho : B1 = B2 = 0 O Ho : B1 = B2 = B3 = B4 = B5 = 0 %3DA police office claims that the proportion of people wearing seat belts is less than 65%. To test this claim, a random sample of 200 drivers is taken and its determined that 126 people are wearing seat belts. The following is the setup for this hypothesis test: Ho :p-0.65 Ha : p < 0.65 In this example, the p-value was determined to be 0.277 come to a conclusion and interpret the results for this hypothesis test for a proportion (use a significance level of 5%) Select the correct answer below: O The decision is to reject the Null Hypothesis. The conclusion is that there is enough evidence to support the claim The decision is to fail to reject the Null Hypothesis. The conclusion is that there is not enough evidence to support the claim
- Calculate the p-value for the following conditions and determine whether or not to reject the null hypothesis. a) one-tail test, z = 1.10, and a = 0.05 b) one-tail test, z; = -2.75, and a = 0.02 c) two-tail test, z = 2.80, and x = 0.05 d) two-tail test, z = -1.54, and α = 0.10 Click here to view page 1 of the cumulative probabilities for the standard normal distribution. Click here to view page 2 of the cumulative probabilities for the standard normal distribution. a) The p-value is (Round to four decimal places as needed.)In a lightbulb factory, an administrator selects a random sample of bulbs produced on assembly line A and a random sample of bulbs produced on assembly line B. The administrator calculates the proportion of malfunctioning bulbs produced by each assembly line and finds that the difference between them (A - B) is 0.008. A researcher conducted a hypothesis test with the following hypotheses: H0: The proportion of malfunctioning bulbs from assembly line A is the sample as the proportion of malfunctioning bulbs from assembly line B. HA: The proportion of malfunctioning bulbs from assembly line A is greater than the proportion of malfunctioning bulbs from assembly line B. She found a P-value of 0.016. What is the best interpretation of this P-value? a If there is no difference in the proportions of all defective parts made on the two assembly lines, the probability of observing a difference of at least 0.008 is 0.016. b If there is a difference of 0.016 in the proportions…A researcher conducts a left-tail hypothesis test. Assume that a = 0.05 (5%). The t statistic from a sample of 25 observations is t = -2.11. Based on this information: a) Would the researcher reject or not reject the null hypothesis? b) Assume that the t test statistic remains the same (i.e. t = -2.11). However, if a = 0.01 (1%), that is, a is smaller this time, then would the researcher reject or not reject the null hypothesis? c) So, the smaller the a, the (easier or harder?) it is to reject the null hypothesis, and therefore the (less or more?) trustworthy the conclusion is.
- We have specified the “tailedness” of a hypothesis test for a population mean with null hypothesis H0: μ = μ0. a. draw the ideal power curve. b. explain what your curve in part (a) portrays. left-tailedConsider the following hypothesis test. H0: u1 - u2 ≤ 0Ha: u1 - u2 > 0 The following results are for two independent samples taken from the two populations. Sample 1 Sample 2 n 1 = 30 n 2 = 50 x 1 = 25.7 x 2 = 22.1 σ 1 = 5.6 σ 2 = 7 a. What is the value of the test statistic (round to 2 decimals)? b. What is the p-value (round to 4 decimals)? Use z-table. Use z-value rounded to 2 decimal places. c. With = .05, what is your hypothesis testing conclusion? p-value is H0My lawn needs mowing , but i do not want to mow if its going to start raining while I'm in the middle of the job. So i am looking at the sky evaluating the weather, using the null hypothesis: "It will rain within the next two hours". In this situation , what would a type I error be?