Calculate the p-value for the following conditions and determine whether or not to reject the null hypothesis.a) one-tail (upper) test, z₂ =2.73, and a = 0.10b) one-tail (lower) test, z = -0.59, and a = 0.05c) two-tail test, zp = -2.29, and a = 0.05d) two-tail test, z=2.09, and a = 0.02Click here to view the first page of the standard normal table. Click here to view the second page of the standard normal tablea) p-value= (Round to four decimal places as needed.)CIS

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Consider the following hypothesis test: Ho: μ=15 Ha: μ≠ 15 A sample of 50 provided a sample mean of 14.15. The Population standard deviation is 3. A). What is the value of the test statistic? ( 2 decimal places) B). What is the P-value? (4 decimal places) C). Using alpha=0.05, is the null hypothesis rejected or not rejected?
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e. Consider the following hypothesis test. H: 4, - H, = 0 H.:H,- H, #0 The following results are for two independent samples taken from the two populations. Sample 1 n, = 70 x; =106 o, = 8.4 a. What is the value of the test statistic? Sample 2 n, = 80 x, =108 0z = 7.6 b. What is the p-value? c. With a=0.01 , using the p-value approach, what is your hypothesis testing conclusion? Why? Explain.
Calculate the p-value for the following conditions and determine whether or not to reject the null hypothesis. a) one-tail (upper) test, z, =2.17, and c=0.10 b) one-tail (lower) test, zn = - 1.49, and a=0.05 c) two-tail test, zn = - 1.71, and o=0.05 d) two-tail test, z, =1.26, and c=0.02 Click here to view the first page of the standard normal table. Click here to view the second page of the standard normal table a) p-value = (Round to four decimal places as needed.) Determine whether or not to reject the null hypothesis. Choose the correct answer below. O A. Reject Ho, since the p-value is less than the significance level o. O B. Do not reject Ho, since the p-value is greater than or equal to the significance level d. O C. Do not reject Ho, since the p-value is less than the significance level o. O D. Reject Ho, since the p-value is greater than or equal to the significance level .
Carry out all nine steps of the hypothesis testing procedure. 1. Assume that anxiety scores as measured by an anxiety assessment inventory are normally distributed with u= 20 and o = 4. anxiety is randomly selected, and their mean anxiety score X = 22. Is the average anxiety score from patients who are under treatment significantly different from 20? Assume a = .10. sample of 4 patients who are undergoing treatment for 2. According to the National ASsociation of Builders, the average single-family home size in the United States is normally distributed with a mean µ = 2392 square feet and a standard deviation o = 760 square feet. Sixty single-family houses are randomly selected from Cleveland, and the mean size is 2,025 square feet. Is the average square footage of houses in Cleveland different than the population mean? Assume a = .05.
Perform the following tests of hypothesis. (a) Ho: 1=285, H1: u< 285, x(mean)=267.80, s=42.90,n=55,a =0.05 (b) Ho: = 10.70,Н1 : u /= 10.70,x(mean)=12.025,s=4.90 n=47 a= 0.01
consider the following hypothesis test H0: u = 22 H a :u (canceled =) 22 A sample of 75 is used and the population standard deviation is 10 . Compute the -value and state your conclusion for each of the following sample results. Use a=0.01. Round value to two decimal places and -value to four decimal places. Enter negative values as negative numbers. a. (mean)=23 z-value p-value b. (mean)= 25.1 z-value p-value c. (mean)=20 z- value p-value
The following MINITAB output presents the results of a hypothesis test for a population mean u. One-Sample T: X Test of mu = 5.5 vs > 5.5 Variable N Mean StDev SE Mean 95% Lower Bound T P х 5 5.92563 0.15755 0.07046 5.77542 6.04 0.002 Is this a one-tailed or two-tailed test? a. b. What is the null hypothesis? Can Ho be rejected at the 1% level? How can you tell? C. d. Use the output and an appropriate table to compute the P-value for the test of Ho: µ 2 6.5 versus H1: µ < 6.5. Use the output and an appropriate table to compute a 99% confidence interval for µ. e.
Calculate the p-value for the following conditions and determine whether or not to reject the null hypothesis. a) one-tail test, z; = 1.40, and a = 0.02 b) one-tail test, z, = - 2.55, and a = 0.10 c) two-tail test, z, = 2.60, and a = 0.02 d) two-tail test, = - 1.66, and a = 0.05 Click here to view page 1 of the cumulative probabilities for the standard normal distribution. Click here to view page 2 of the cumulative probabilities for the standard normal distribution.
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Calculate the p-value for the following conditions and determine whether or not to reject the null hypothesis. Complete parts a through d. a. One-tail (lower) test, zp = -1.19, and x = 0.05. p-value= (Round to four decimal places as needed.)
1.) Conclusion fail to reject the null hypothesis and do not support the claim reject the null hypothesis and support the claim

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Calculate the p-value for the following conditions and determine whether or not to reject the null hypothesis. a) one-tail (upper) test, z = 2.73, and a = 0.10 b) one-tail (lower) test, z = -0.59, and a = 0.05 c) two-tail test, z₂ = -2.29, and a = 0.05