Complete the following hypothesis test.Ho:o2 < 4.36Ha:o > 4.36 (Claim)s2 = 3.6 , a = 0.10 and n = 29Finda. The Critical Valueb. The Test Statistic x%3DThe Chi-Square Test Statistic Degrees of Freedom(n – 1)s²n – 1g2c. Is this a left, right or two tailed test?O right-tailedO left-tailedO two-tailed

Answered: Complete the following hypothesis test.…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A hypothesis test is performed at the 5% significance for a normal population mean u iwth the null and alternative hypotheses given below. Haitl# Ho Orl =r1:0H It is found that the p-value is p = 0.0123. What is the correct decision and interpretation of the hypothesis test? O Inconclusive or not enough information to tell. O Do not reject the null hypothesis. Our data supports the null hypothesis. O Do not reject the null hypothesis. We have proved the null hypothesis is true. O Reject the null hypothesis. We have proved the null hypothesis is false. O Reject the null hypothesis. Our data is statistically insignificant. O Reject the null hypothesis. Our data does not support the null hypothesis.
Test the claim that the mean GPA of night students is larger than 2.6 at the 0.01 significance level. The null and alternative hypothesis would be: Ho:p > 0.65 Ho:p 2.6 H1:p 0.65 H1:p+ 0.65 H1:µ > 2.6 H1:µ + 2.6 H:µ < 2.6 %3D The test is: two-tailed right-tailed left-tailed Based on a sample of 65 people, the sample mean GPA was 2.63 with a standard deviation of 0.07 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis
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A test of the hypotheses, Ho: p s 0.24 and H1: p > 0.24 is a one-tailed test two-tailed test test of two sample means test of two sample proportions
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What is the critical t score if you are testing a one-tailed hypothesis, α level of .05 with df = 36? a. 1.671 b. 2.026 c. 2.028 d. 1.697
Only C and D
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For the hypothesis system H0: u=c versus Ha: u doesn't equal c Give the absolute value of the calculated test statistics which would correspond to the standard P-value. Consider the population normally distributed. P-value= 0.026
Test the daim that the proportion of men who own cats is significan tly different than the proportion of women who own cats at the 0.02 significance level. The null and alternative hypothesis would be: Ho:PM = PF Ho:HM PF Ho:PM µp H1:µM PF H1:µM + HF The test is left-tailed two-tailed right-tailed Based on a sample of 80 men, 40% owned cats Based on a sample of 20 women, 50% owned cats positive Critical Value = [three decimal accuracy] Test Statistic = [three decimal accuracy] Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
Three students, an athlete, a fraternity member, and an honors student, record the number of hours they slept each night for 20 nights. O JMP Applet imp ? Oneway Analysis of Sleep Hours By Student Oneway Analysis of Sleep Hours By Student 10 Oneway Anova 14 Summary of Fit 12 Rsquare 0.024506 10- Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) -0.00072 1.99517 7.7 60 Analysis of Variance Sum of Mean F Prob > Source DF Squares Square Ratio F 2 Athiete Frat Honors Student 2 5.70000 2.85000 0.7180 0.4931 Student Error 57 226.90000 3.98070 C. Total 59 232.60000 Oneway Anova Means for Oneway Anova Std Lower Upper 95% Summary of Fit Level Number Mean Error 95% Athlete 20 8.10000 0.44813 7.2086 8.9934 Rsquare 0.024506 Frat 20 7.65000 0.44813 6.7588 8.5434 Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) -0.00972 Honors 20 7.35000 0.44813 6.4586 8.2434 1.99517 Std Error uses a pooled estimate of error variance 7.7 60 Analysis of…
Test the claim about the population variance o² at the level of significance a. Assume the population is normally distributed. Claim: o² ≤17.1; x = 0.01 Sample statistics: s² = 25.13, n = 41 Write the null and alternative hypotheses. Ho: H₂:0²

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