Example 9.7.1 showed that the following statement is true: For each integer n > 2, n(n - 1) n (equation 1). 2 Use this statement to justify the following. (:::)- n + 3 (n + 3)(n + 2) for each integer n 2 -1. 2 Solution: Let n be any integer with n 2 -1. Sincen + 3 2 , we can substitute n + 3 in place of n in equation 1 to obtain )-). n+ 3 (:) - n + n + 3 %3D By simplifying and factoring the numerator on the right hand side of this equation we conclude (n+3)(n+2) (*::) - n + 3 n +
Example 9.7.1 showed that the following statement is true: For each integer n > 2, n(n - 1) n (equation 1). 2 Use this statement to justify the following. (:::)- n + 3 (n + 3)(n + 2) for each integer n 2 -1. 2 Solution: Let n be any integer with n 2 -1. Sincen + 3 2 , we can substitute n + 3 in place of n in equation 1 to obtain )-). n+ 3 (:) - n + n + 3 %3D By simplifying and factoring the numerator on the right hand side of this equation we conclude (n+3)(n+2) (*::) - n + 3 n +
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![Example 9.7.1 showed that the following statement is true:
For each integer n > 2,
n(n – 1)
(equation 1).
2
Use this statement to justify the following.
n + 3
(n + 3)(n + 2) for each integer n 2 -1.
%D
n + 1
2
Solution: Let n be any integer withn 2 -1. Since n + 3 2
we can substitute n + 3
in place of n in equation 1 to obtain
(:?) - (-+3
n + 3
n + 3
n + 1
By simplifying and factoring the numerator on the right hand side of this equation we conclude
::) - (n+ 3)(n+2)
n + 3
n + 1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcb24ab9a-ef38-426b-8ace-7e5b0ab09afd%2F1e517630-e5de-4a2e-969d-1e23c65f8eff%2Fak3kat_processed.png&w=3840&q=75)
Transcribed Image Text:Example 9.7.1 showed that the following statement is true:
For each integer n > 2,
n(n – 1)
(equation 1).
2
Use this statement to justify the following.
n + 3
(n + 3)(n + 2) for each integer n 2 -1.
%D
n + 1
2
Solution: Let n be any integer withn 2 -1. Since n + 3 2
we can substitute n + 3
in place of n in equation 1 to obtain
(:?) - (-+3
n + 3
n + 3
n + 1
By simplifying and factoring the numerator on the right hand side of this equation we conclude
::) - (n+ 3)(n+2)
n + 3
n + 1
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