Show that if n is a positive integer, then fo(n) (26(n) $(2n) = if n is odd if n is even.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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**Problem 4:**

Show that if \( n \) is a positive integer, then:

\[
\phi(2n) = 
\begin{cases} 
\phi(n) & \text{if } n \text{ is odd} \\
2\phi(n) & \text{if } n \text{ is even} 
\end{cases}
\]

Here, \(\phi(n)\) represents Euler's totient function, which counts the number of positive integers up to \( n \) that are relatively prime to \( n \).
Transcribed Image Text:**Problem 4:** Show that if \( n \) is a positive integer, then: \[ \phi(2n) = \begin{cases} \phi(n) & \text{if } n \text{ is odd} \\ 2\phi(n) & \text{if } n \text{ is even} \end{cases} \] Here, \(\phi(n)\) represents Euler's totient function, which counts the number of positive integers up to \( n \) that are relatively prime to \( n \).
Expert Solution
Step 1

Given- n is a positive integer.

To prove- ϕ2n=ϕn     if n is odd2ϕn   if n is even

 

Result Used- 

  • ϕmn=ϕmϕn if gcdm, n = 1
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