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n(n-1) 2 this statement to justify the following. (n+³) = - :)-( (equation 1). 2 (n + 3)(n + 2) 2 tion: Let n be any integer with n 2-1. Since n +32 2 ( for each integer n 2 -1. n+3 )-¹). , we can substitute n +3 mplifying and factoring the numerator on the right hand side of this equation we conclude in place of n in equation 1 to obtain

n(n-1) 2 this statement to justify the following. (n+³) = - :)-( (equation 1). 2 (n + 3)(n + 2) 2 tion: Let n be any integer with n 2-1. Since n +32 2 ( for each integer n 2 -1. n+3 )-¹). , we can substitute n +3 mplifying and factoring the numerator on the right hand side of this equation we conclude in place of n in equation 1 to obtain

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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For each integer n ≥ 2, (₁²₂) = ² Use this statement to justify the following. (2+3)=([ (+)- n(n-1) 2 3 (n+³)= (n + 3) (n + 2), for each integer n ≥ −1. 2 = Solution: Let n be any integer with n 2-1. Since n + 3 ≥ 2 = (equation 1). 2 n+3 By simplifying and factoring the numerator on the right hand side of this equation we conclude )-₁) , we can substitute 7+ 3 in place of n in equation 1 to obtain
Transcribed Image Text:For each integer n ≥ 2, (₁²₂) = ² Use this statement to justify the following. (2+3)=([ (+)- n(n-1) 2 3 (n+³)= (n + 3) (n + 2), for each integer n ≥ −1. 2 = Solution: Let n be any integer with n 2-1. Since n + 3 ≥ 2 = (equation 1). 2 n+3 By simplifying and factoring the numerator on the right hand side of this equation we conclude )-₁) , we can substitute 7+ 3 in place of n in equation 1 to obtain
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