Example 5.2: - Formation water sample with solids concentrations of calcium(Ca) = 460 ppm, sulfate (SO4) = 1,400 ppm, and Na plus Cl = 19,000 ppm.Find Equivalent NaCl solution in ppm. SchlumbergerGeneralEstimation of Formation Temperature with DepthGen-2(former Gen-6)GenTemperature gradient conversions: 1°F/100 ft = 1.823°C/100 m1°C/100 m = 0.5486°F/100 ftAnnual meansurface temperatureTemperature (°C)275075100125150175162550751001251501751520.60.81.01.2 1.4 1.6°F/100 ftGeothermal gradient310PA41.091,461.822.192.55 2.92°C/100 mDepth(thousandsof feet)Depth(thousandsof meters)15520258010015020025030035060100150200250300350Temperature (°F)Annual meansurface temperature© Schlumberger

Given data: The concentration of Ca=460 ppm The concentration of SO4=1400 ppm The concentration of…

Answered: Example 5.2: - Formation water sample…

Example 5.2: - Formation water sample with solids concentrations of calcium (Ca) = 460 ppm, sulfate (SO4) = 1,400 ppm, and Na plus Cl = 19,000 ppm. %3D Find Equivalent NaCl solution in ppm.

Structural Analysis

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ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Example 5.2: - Formation water sample with solids concentrations of calcium
(Ca) = 460 ppm, sulfate (SO4) = 1,400 ppm, and Na plus Cl = 19,000 ppm.
Find Equivalent NaCl solution in ppm.

Schlumberger
General
Estimation of Formation Temperature with Depth
Gen-2
(former Gen-6)
Gen
Temperature gradient conversions: 1°F/100 ft = 1.823°C/100 m
1°C/100 m = 0.5486°F/100 ft
Annual mean
surface temperature
Temperature (°C)
27
50
75
100
125
150
175
16
25
50
75
100
125
150
175
1
5
2
0.6
0.8
1.0
1.2 1.4 1.6°F/100 ft
Geothermal gradient
3
10
PA
4
1.09
1,46
1.82
2.19
2.55 2.92°C/100 m
Depth
(thousands
of feet)
Depth
(thousands
of meters)
15
5
20
25
80
100
150
200
250
300
350
60
100
150
200
250
300
350
Temperature (°F)
Annual mean
surface temperature
© Schlumberger

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