Example 3.2: For the circuit shown in Fig. 3.6, find the node voltages. Solution: The supernode contains the 2-V source 10 2 ww 2, and the 10-2 resistor. Applying 2V supernode as shown in Fig. 3.7(a) gives 2 = i + iz + 7 Expressing i and iz in terms of the nod 7A 2A v2 – 0 v1 -0 2 + 7 %3D or --20 - 2v1
Example 3.2: For the circuit shown in Fig. 3.6, find the node voltages. Solution: The supernode contains the 2-V source 10 2 ww 2, and the 10-2 resistor. Applying 2V supernode as shown in Fig. 3.7(a) gives 2 = i + iz + 7 Expressing i and iz in terms of the nod 7A 2A v2 – 0 v1 -0 2 + 7 %3D or --20 - 2v1
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
Related questions
Question
![mponent of nódal
ch element. There is no way of knowing the current through
wever, KCL must be satisfied at a sunernode like any other node. Hence a tde
spernode in Fig. 3.5,
i + i4 = i2 + i3
(3.11a)
v1 - v2
v1 - v3
v2 – 0
v3 - 0
(3.11b)
6.
To apply Kirchhoff's voltage law to the supernode in Fig. 3.4 we redraw the circuit as
shown in Fig. 3.5. Going around the loop in the clockwise»direction gives
-V2 + 5 + v3 = 0=v2 – V3 = 5
(3.12)
From Eqs. (3.10), (3.11b), and (3.12), we obtain the node volltages.
5V
د مُسق ک من ؤ
Figure 3.5 Applying KVL to a supernode.
Example 3.2: For the circuit shown in Fig. 3.6, find the node voltages.
Solution:
The supernode contains the 2-V source, nodes 1 and
10 2
www
2, and the 10-2 resistor. Applying KCL to the
2 V
supernode as shown in Fig. 3.7(a) gives
2.
12
2 = i + iz +7
7 A
Expressing in and iz in terms of the node voltages
2 A
22
v1 - 0
v2 - 0
2 =
7
4
or
(3.2.1)
V2 =-20 - 2vVI
Figure 3.6 For Example 3.2.
ESTHRER: ALI SHARAAN
METHORS OF ANALYSIS
CHAPTER 3
Kel
emed
gincerin](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa2ec50aa-a59e-43c9-a752-954ac5032aee%2Fa4f84604-e9fe-4fe9-bdd0-cc2ef4e1d536%2F52iqqa6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:mponent of nódal
ch element. There is no way of knowing the current through
wever, KCL must be satisfied at a sunernode like any other node. Hence a tde
spernode in Fig. 3.5,
i + i4 = i2 + i3
(3.11a)
v1 - v2
v1 - v3
v2 – 0
v3 - 0
(3.11b)
6.
To apply Kirchhoff's voltage law to the supernode in Fig. 3.4 we redraw the circuit as
shown in Fig. 3.5. Going around the loop in the clockwise»direction gives
-V2 + 5 + v3 = 0=v2 – V3 = 5
(3.12)
From Eqs. (3.10), (3.11b), and (3.12), we obtain the node volltages.
5V
د مُسق ک من ؤ
Figure 3.5 Applying KVL to a supernode.
Example 3.2: For the circuit shown in Fig. 3.6, find the node voltages.
Solution:
The supernode contains the 2-V source, nodes 1 and
10 2
www
2, and the 10-2 resistor. Applying KCL to the
2 V
supernode as shown in Fig. 3.7(a) gives
2.
12
2 = i + iz +7
7 A
Expressing in and iz in terms of the node voltages
2 A
22
v1 - 0
v2 - 0
2 =
7
4
or
(3.2.1)
V2 =-20 - 2vVI
Figure 3.6 For Example 3.2.
ESTHRER: ALI SHARAAN
METHORS OF ANALYSIS
CHAPTER 3
Kel
emed
gincerin
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