solve exercise applying mesh analysis 110 VccR₁ = 1.466,67+ VRIizi3 +R3=628,572VR3R2=733,332xR211I2

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Answered: 110 Vcc R₁ = 1.466,67 + VRI iz i3 +…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Give an independent set of linear that can ve solved for the current shown. Use the Junction Rule
A5
Shown in the figure below is an electrical circuit containing three resistors and two batteries. R1 10 R2 I2 R3 Write down the Kirchhoff Junction equation and solve it forI, in terms of J, and I. Write the result here: Write down the Kirchhoff Loop equation for a loop that starts at the lower left comer and follows the perimeter of the circuit diagram dockwise. Write down the Kirchhoff Loop equation for a loop that starts at the lower left comer and touches the components 4V, R, and Rg. The resistors in the circuit have the following values: . R,70 • R=10 Solve for all the following (some answers may be negative): Amperes Amperes Amperes
Shown in the figure below is an electrical circuit containing three resistors and two batteries. R3 10 R2 R1 Write down the Kirchhoff Junction equation and solve it for I, in terms of I, and Iz. Write the result here: Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and follows the perimeter of the circuit diagram clockwise. Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and touches the components R1, R2, and 4V. The resistors in the circuit have the following values: R, = 130 • R2 = 50 R3 = 10 Solve for all the following (some answers may be negative): | Amperes I = I, = Amperes Iz = Amperes NOTE: For the equations, put in resistances and currents SYMBOLICALLY using variables like RR2,R3 and I,,12,13. Use numerical values of 10 and 4 for the voltages.
Although we are given the restrictions on Kd and Kp, explain how we arrived at that conclusion and show all work necessary to arrive at the given solution for each restriction.

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110 Vcc R₁ = 1.466,67 + VRI iz i3 + R3=628,572 VR3 R2=733,332 x R2 11 I2