Example 2.16 A 2.5 m wide rectangular channel carries 6.0 m³/s of flow at a depth of 0.50 m. Calculate the minimum height of a streamlined, flat topped bump required to be placed at a section to cause critical flow over the hump. The energy loss over the hump can be taken as 10% of the upstream velocity head. Solution: Discharge intensity q = 6.0/2.5 = 2.40 m³/s/m Refer to Figure 2.22. Energy Line D V²/2, E₁ Yc2 Hump ΔΖ E₂ = Ecz 2
Example 2.16 A 2.5 m wide rectangular channel carries 6.0 m³/s of flow at a depth of 0.50 m. Calculate the minimum height of a streamlined, flat topped bump required to be placed at a section to cause critical flow over the hump. The energy loss over the hump can be taken as 10% of the upstream velocity head. Solution: Discharge intensity q = 6.0/2.5 = 2.40 m³/s/m Refer to Figure 2.22. Energy Line D V²/2, E₁ Yc2 Hump ΔΖ E₂ = Ecz 2
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![Example 2.16
A 2.5 m wide rectangular channel carries 6.0 m³/s of flow at a depth of 0.50 m. Calculate the
minimum height of a streamlined, flat topped bump required to be placed at a section to cause critical
flow over the hump. The energy loss over the hump can be taken as 10% of the upstream velocity head.
Solution: Discharge intensity q = 6.0/2.5 = 2.40 m³/s/m Refer to Figure 2.22.
Energy Line
K
V²/2,
E₁
y cz
Hump AZ
E₂ = Ec₂
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc98808cc-a04d-439c-b309-b71e5f40ec7d%2Fa142ed72-cdcf-497a-b884-f98653f0e325%2Fwhp4zt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Example 2.16
A 2.5 m wide rectangular channel carries 6.0 m³/s of flow at a depth of 0.50 m. Calculate the
minimum height of a streamlined, flat topped bump required to be placed at a section to cause critical
flow over the hump. The energy loss over the hump can be taken as 10% of the upstream velocity head.
Solution: Discharge intensity q = 6.0/2.5 = 2.40 m³/s/m Refer to Figure 2.22.
Energy Line
K
V²/2,
E₁
y cz
Hump AZ
E₂ = Ec₂
2
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